All categories

3 years ago

200+10x=y 140+40x=y I need that solved

Mathematics

1 answer:

kherson [118]3 years ago

3 0

Answer:

(2,220)

Step-by-step explanation:

if you have any questions about the way I solved it, don't hesitate to ask

You might be interested in

IMMEDIATE HELP PLS THANKS <33

Ksenya-84 [330]

Reflect across the y axis and moved through the translation x = 2

3 0

4 years ago

ethan bought 4 packages of pencils. after he gave 8 pencils to his friends, he had 40 pencils left over. how many pencils were i

marishachu [46]

Answer:

there was 12 pencil's in each package because 12 ×4=48 48 -8=40

4 0

3 years ago

Solve the following equation -2|x-4|+7=-3

algol [13]

-2|x-4|+7 = -3

-2|x-4| = -10

|x-4| = 5

Two forms:

x-4 = 5 : x = 9
or
x-4 = -5 : x = -1

7 0

3 years ago

16r^4t-6r^3t^2+4rt^2=

DochEvi [55]

Answer:

$2rt(8r^3-3r^2t+2t)$

Step-by-step explanation:

We have been given a polynomial $16r^4t-6r^3t^2+4rt^2$ and we are supposed to simplify our polynomial.

We will use factoring to simplify our polynomial. Let us factor out the greatest common factor of all the terms.

We can see that 16, 6 and 4 has 2 as their greatest common factor.

The greatest common factor of $r^4, r^3,r$ is r.

The greatest common factor of $t, t^2, t^2$ is t.

So the greatest common factor of the terms of our expression will be $2rt$ .

Let us factor out $2rt$ from our given polynomial.

$2rt(8r^3-3r^2t+2t)$

As we can not factor our expression more, therefore, we will get $2rt(8r^3-3r^2t+2t)$ after simplifying our polynomial.

5 0

3 years ago

Approximately 80,000 marriages took place in the state of New York last year. Estimate the probability that for at least one of

sasho [114]

Answer:

a)0,45119

b)1

Step-by-step explanation:

For part A of the problem we must first find the probability that both people in the couple have the same birthday (April 30)

$P=\frac{1}{365} *\frac{1}{365}=\frac{1}{133225} \\$

Now the poisson approximation is used

λ=nP=80000*1/133225=0,6

Now, let X be the number of couples that birth April 30

P(X ≥ 1) =

1 − P(X = 0) =

$1-\frac{(e^-0.6)*(-0,6)^{0} }{0!}$

P(X ≥ 1) = 0,45119

B) Now want to find the

probability that both partners celebrated their birthday on th, assuming that the year is 52 weeks and therefore 52 thursday

$P=52*\frac{1}{365} *\frac{1}{365}=\frac{52}{133225} \\$

Now the poisson approximation is used

λ=nP=80000*52/133225=31.225

Now, let X be the number of couples that birth same day

P(X ≥ 1) =

1 − P(X = 0) =

$1-\frac{(e^-31.225)*(-31.225)^{0} }{0!}$

P(X ≥ 1) = 1

6 0

3 years ago