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Nutka1998 [239]
3 years ago
6

Write an equation from the following points (plug in the numbers you would use for "m" and "b"):

Mathematics
1 answer:
Annette [7]3 years ago
4 0

Answer:

y =\fracc{4}{3}x+5

m=4/3 and b=5

Step-by-step explanation:

We want to find the equation of the line passing through (3,9) and (6,13).

We determine the slope using:

m =  \frac{y_2-y_1}{x_2-x_1}

Let:

(x_1=3,y_1=9), (x_2=6,y_2=13)

We substitute the points to get:

m =  \frac{13 - 9}{6 - 3}  =  \frac{4}{3}

We now use the formula:

y-y_1=m(x-x_1)

We substitute to get:

y - 9 =  \frac{4}{3} (x - 3)

Multiply through by 3 to get;

3y - 27 = 4(x - 3)

We expand further to get:

3y - 27 = 4x - 12

This implies that:

4x - 3y  = - 15

We solve for y to get:

y =\fracc{4}{3}x+5

Therefore m=4/3 and b=5

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Which of the following equations have complex roots?
mestny [16]

Answer:

A

Step-by-step explanation:

Complex roots of quadratic functions occur when the <u>discriminant is negative</u>.

<u>Discriminant</u>

b^2-4ac\quad\textsf{when}\:\:ax^2+bx+c=0

Evaluate the discriminant of each of the given equations.

\textsf{A.} \quad 3x^2+2=0

\implies a=3, \quad b=0, \quad c=2

\implies b^2-4ac=0^2-4(3)(2)=-24

As -24 < 0 the equation will have complex roots.

\textsf{B.} \quad 2x^2+1=7x

\implies 2x^2-7x+1=0

\implies a=2, \quad b=-7, \quad c=1

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As 41 > 0 the equation does not have complex roots.

\textsf{C.} \quad 3x^2-1=6x

\implies 3x^2-6x-1=0

\implies a=3, \quad b=-6, \quad c=-1

\implies b^2-4ac=(-6)^2-4(3)(-1)=48

As 48 > 0 the equation does not have complex roots.

\textsf{D.} \quad 2x^2-1=5x

\implies 2x^2-5x-1=0

\implies a=2, \quad b=-5, \quad c=-1

\implies b^2-4ac=(-5)^2-4(2)(-1)=33

As 33 > 0 the equation does not have complex roots.

Learn more about discriminants here:

brainly.com/question/27444516

brainly.com/question/27869538

Learn more about complex roots here:

brainly.com/question/26344541

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2 years ago
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3 years ago
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Answer:

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Step-by-step explanation:

3x+2y=12

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at memorial hospital 9 of the 12 babies born on Tuesday were boys In simplest form What fraction of the babies born on Tuesday w
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