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Nutka1998 [239]
3 years ago
6

Write an equation from the following points (plug in the numbers you would use for "m" and "b"):

Mathematics
1 answer:
Annette [7]3 years ago
4 0

Answer:

y =\fracc{4}{3}x+5

m=4/3 and b=5

Step-by-step explanation:

We want to find the equation of the line passing through (3,9) and (6,13).

We determine the slope using:

m =  \frac{y_2-y_1}{x_2-x_1}

Let:

(x_1=3,y_1=9), (x_2=6,y_2=13)

We substitute the points to get:

m =  \frac{13 - 9}{6 - 3}  =  \frac{4}{3}

We now use the formula:

y-y_1=m(x-x_1)

We substitute to get:

y - 9 =  \frac{4}{3} (x - 3)

Multiply through by 3 to get;

3y - 27 = 4(x - 3)

We expand further to get:

3y - 27 = 4x - 12

This implies that:

4x - 3y  = - 15

We solve for y to get:

y =\fracc{4}{3}x+5

Therefore m=4/3 and b=5

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So if both cot(<em>θ</em>) and cos(<em>θ</em>) are negative, that means sin(<em>θ</em>) must be positive.

Recall that

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