Question

Find the value of y in the equation

Answer 1

Answer:

The value of $y = 2\frac{3}{8}$

Step-by-step explanation:

Given an equation : $\frac{3}{y-2}=8$

Cross multiplying states that  multiplying the numerator of each fraction by the other's denominator.

$\frac{a}{b}= \frac{c}{d}$ or

$a\cdot d = b \cdot c$

Now, we use cross multiply for the given equation:

we can write it as : $\frac{3}{y-2}=\frac{8}{1}$

then, $3\cdot 1 = (y-2) \cdot 8$

Using distributive property on right hand side : $a(b-c)= a\cdot b- a\cdot c$

we have,

$3=8y-16$

Adding 16 both the sides we get,

$3+16=8y-16+16$

Simplify:

$8y = 19$

Divide by 8 both sides, we get

$y=\frac{19}{8}$ or $y = 2\frac{3}{8}$

therefore, the value of y is, $y = 2\frac{3}{8}$

Answer 2

It should be y=19/8.
Is it multiple choice.