Answer:

Step-by-step explanation:
Assuming this complete question:
"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean
kilograms and standard deviation
kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.
"
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where
and 
And the best way to solve this problem is using the normal standard distribution and the z score given by:

We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.
We can convert the corresponding z score for x=42.6 like this:

So then the corresponding z scale would be:

Answer:
Th number of pages is 33
Step-by-step explanation:
The ratio of the number of pages of text shown in the illustration is 3:2. This implies that for every 2 pages of illustrations, there are 3 pages of text. Therefore, for 22 pages of illustration we shall have;
2 page of illustration = 3 page of text
Then
22 page of illustration = x pages of text
Then by Cross multiplication


x =
x = 33
Answer:
-9
Step-by-step explanation:
you'd add 2 to the -11 which would equal -9 and leave you with x=-9
Answer:
Step-by-step explanation:
I am looking for the answers and I can’t find it
Answer:
Yes. In general, the set of rational numbers is closed under addition, subtraction, and multiplication; and the set of rational numbers without zero is closed under division.
Step-by-step explanation:
:)