Answer:
Step-by-step explanation:
Applying double angle identity:
Doing so would give:
We need to get everything to one side so we have 0 on one side.
Subtract 1 on both sides:
Add on both sides:
Let's factor the left-hand side.
The two terms on the left-hand side have a common factor of .
.
This implies we have:
.
We need to solve both equations.
You are asking they be solved in the interval .
This means look at your unit circle and find when you have your y-coordinates is 0.
You this at 0 and . (I didn't include because you don't have a equal sign at the endpoint of .
Now let's solve
Subtract 1 on both sides:
Divide both sides by 2:
Now we are going to go and look for when the y-coordinates are -1/2.
This happens at and .
The solution set given the restrictions is
The vertices are the following intersection points:
1) y = 0 and x 0 0 => (0,0)
2) x = 0 and 2x - 6y = - 3 => (0, 1/2) = (0, 0.5)
3) 2x + 3y = 6 and 2x - 6y = - 3 => (3/2, 1) = (1.5, 1)
4) y = 0 and 2x + 3y = 6 => (3,0)
Answer: (0,0) , (0, 0.5) (1.5, 1), (3, 0) = the third option.
It is b because b is the most logical answer
Answer:
Step-by-step explanation:
The skope-intercept form:
m - slope
b - y-intercept
The formula of a slope:
We have the points (2, -1) and (5, -3). Substitute:
We have the equation:
Put the coordinates of the point (2 , -1) to the equation:
<em>add 4/3 to both sides</em>
Finally we have:
|x - 3| - 1 = 5
x - 3 - 1 = 5
x - 4 = 5
x = 9
-(x - 3) - 1 = 5
-x + 3 - 1 = 5
-x + 2 = 5
-x = 3
x = - 3
x = -3 , 9 matched the answers on the number line
Answer is B) |x - 3| - 1 = 5