Given:
<span>11 11.5 10.5 17 14.5 14.5 18 17 19
Arrange in chronological order from least to greatest.
10.5 ; 11 ; 11.5 ; 14.5 ; 14.5 ; 17 ; 17 ; 18 ; 19
</span><span>I used an online lower and upper fence calculator to get the necessary data.
Minimum: 10.5
Maximum: 19
Q1: 11.25
Q2 or median: 14.5
Q3: 17.5
Interquartile range can be solved by subtracting the value of Q1 from the value of Q3
IQR = Q3 - Q1
IQR = 17.5 - 11.25
IQR = 6.25 CHOICE A. </span>
Answer:
I believe it should be b and d
Step-by-step explanation:
hoped it helped :)
Two hundred and seventy three point two hundred and sixty one
See, in these type of questions always first assume your original price to be x. And now try to write whatever information is given to you.
Now, you have that it has been sold for 12% profit, so basically it is sold at. (1 + (12/100))x = 1.12x
Now it is given that if it had been sold for 33₹ more. I.e. if it had been sold at. 1.12x + 33
Net gain would have been 14%.
So gain of 14%, means the cost to be (1+(14/100))x = 1.14x
And basically both 1.12x +33 and 1.14x are final costs, so
1.14x = 1.12x + 3
=> 1.14x - 1.12x = 3
=> 0.02x = 3
=> x = 3÷0.02
=> x= 1650₹
So original cost is 1650₹.
Hope you understand the solution and the way to tackle these type of problems if not then let me know.
hope it helps
pls mark my anwers as brainiest
