Yes you are right. it's 132
Answer:
correct option is C) 2.8
Step-by-step explanation:
given data
string vibrates form = 8 loops
in water loop formed = 10 loops
solution
we consider mass of stone = m
string length = l
frequency of tuning = f
volume = v
density of stone =
case (1)
when 8 loop form with 2 adjacent node is
so here
..............1

and we know velocity is express as
velocity = frequency × wavelength .....................2
= f ×
here tension = mg
so
= f ×
..........................3
and
case (2)
when 8 loop form with 2 adjacent node is
..............4

when block is immersed
equilibrium eq will be
Tenion + force of buoyancy = mg
T + v ×
× g = mg
and
T = v ×
- v ×
× g
from equation 2
f ×
= f ×
.......................5
now we divide eq 5 by the eq 3

solve irt we get

so
relative density 
relative density = 2.78 ≈ 2.8
so correct option is C) 2.8
Answer:
The function is y = 40 * 2^(x/2)
The graph is in the image attached
Step-by-step explanation:
The function that models this growth is an exponencial function, that can be described with the following equation:
y = a * b^(x/n)
Where a is the inicial value, b is the rate of growth, x is the time and n is the relation between the time and the rate (the rate occurs for every two hours, so n = 2).
Then, using a = 40, r = 2 and n = 2, we have:
y = 40 * 2^(x/2)
If we plot this function, we have the graph shown in the image attached,
It is an exponencial graph, where the value of y increases very fast in relation to the increase of x.