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Complete question
The number of absences per student in each of two classes is shown on the dot plots below.
A dot plot titled Number of absences per student in Misses Anderson's class. The number line goes from 0 to 6. There is 1 dot above 0, 3 above 1, 3 above 2, 3 above 3, 1 above 4, and 0 above 5 and 6.
A dot plot titled Number of absences per student in Misses Bergot's class. The number line goes from 0 to 6. There is 1 dot above 0, 1 above 1, 2 above 2, 3 above 3, 2 above 4, 1 above 5, and 1 above 6.
Which statements accurately compare the two data sets? Select three options.
a. The mean number of absences is greater in Mrs. Anderson’s class.
b. The mean number of absences is greater in Mrs. Bergot’s class.
c. There is more variability in Mrs. Anderson’s data set.
d. There is more variability in Mrs. Bergot’s data set.
e. The mean and MAD are better representations of these data sets than the median and IQR.
Answer:
b. The mean number of absences is greater in Mrs. Bergot’s class.
d. There is more variability in Mrs. Bergot’s data set.
e. The mean and MAD are better representations of these data sets than the median and IQR.
Step-by-step explanation:
From the above data given in the question and the options given to us, we can observe from the comparison of both the number of absences in Mrs Bergot's class to that in Mrs Anderson's class, there will be a presence of variation in the data of one of the classes and that class happens to be Mrs Bergot's class.
The appropriate statistical tool that we can be used to determine and measure the centre of variability of the data is Mean and Mean Absolute Deviation.
EOF Is A 80 Degree Angle FOB Is A 180 Degree Angle BOC Is A 90 Degree Angle.
Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
5 loaves* (176 slices/ 8 loaves)= 110 slices.
(Note that the unit cancels out so you get the answer)
There are 110 slices of bread in 5 loaves~
Answer:
Try finding some place with cheap screen fixing prices. If you can't, ask a friend if they know how to do this type of stuff.
Step-by-step explanation:
