For a function to begin to qualify as differentiable, it would need to be continuous, and to that end you would require that
is such that

Obviously, both limits are 0, so
is indeed continuous at
.
Now, for
to be differentiable everywhere, its derivative
must be continuous over its domain. So take the derivative, noting that we can't really say anything about the endpoints of the given intervals:

and at this time, we don't know what's going on at
, so we omit that case. We want
to be continuous, so we require that

from which it follows that
.
Answer:

Step-by-step explanation:
We can solve the problem in this way:
- The 1st information that we have is that the four numbers are even and consecutive integer. Let's call these numbers A, B, C and D. This means that:

(since the distance between two even consecutive numbers is 2)
- The 2nd information that is given is that the sum of the first and third multiplied by 3 equals 28 less than 5 times the fourth, so:
(1)
Now we rewrite eq(1) by using:

and
(obtained by combining the 3 first equations)
So we get:

Solving this equation for C,

So the other numbers are:

Answer:
6x - 13y
Step-by-step explanation:
5(2x - 2y) - (4x + 3y)
10x - 10y - 4x - 3y
10x - 4x - 10y - 3y
6x - 13y
Answer:
In a translation, ALL of the points move the same distance in the same direction. A translation is called a rigid transformation or isometry because the image is the same size and shape as the pre-image.
Step-by-step explanation: