Answer:
ok fking fk it ill just tell you, the most affordable way is doing it as a 4*3 package, the length will be 16, width 12, and the height 5. the area will be 960in^3, and the SA will be 664 in^2
Step-by-step explanation:
Answer:
There is a 99.99998% probability that at least one valve opens.
Step-by-step explanation:
For each valve there are only two possible outcomes. Either it opens on demand, or it does not. This means that we use the binomial probability distribution to solve this problem.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinatios of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
In this problem we have that:

Calculate P(at least one valve opens).
This is 
Either no valves open, or at least one does. The sum of the probabilities of these events is decimal 1. So:


So


Finally

There is a 99.99998% probability that at least one valve opens.
Answer:
56
Step-by-step explanation:
Three and one hundred forty one hundredths <span />
Answer:
cosine = adjacent / hypotenuse
cosine 62º = JL / 17
JL = cosine 62º * 17
JL = .47 * 17
JL = 7.99
JL = 8.0
Step-by-step explanation: