The first equation uses the first and second coupons. the coupon (1-y)40 will take y% off of the dress pants so the answer is 40(1-y)
Answer:

Step-by-step explanation:
<u>Given:</u>
Base = b = 2 in.
Perpendicular = a = 2 in.
<u>Required:</u>
Hypotenuse = c = ?
<u>Formula:</u>
(Pythagoras Theorem)
<u>Solution:</u>
c² = (2)² + (2)²
c² = 4 + 4
c² = 8
Taking sqrt on both sides
c = 2.8 in.
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Suppose we have a triangle ΔABC,
Length of AB = 14
Length of AC = 14
Angle ∠BAC = 122 degree
This triangle is isosceles triangle so, angle B = angle C = (180 - 122)/2 = 29
We know the two side and one angle of triangle ABC, here we use Sine Rule.
(In trigonometry, the law of sines, sine law, sine formula, or sine rule is an equation relating the lengths of the sides of a triangle (any shape) to the sines of its angles.)
According to the law,


Solve for a
a = 24.49 option C
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