Question

The sum of the following algebraic expression 2x + 15, 7-8x and 3x - 41 is 30 find the value of x..​

Answer 1

$\\ \tt \longmapsto2x + 15 + 7 - 8x + 3x - 41 = 30 \\ \\ \tt \longmapsto 2x - 8x + 3x + 15 + 7 - 41 = 30 \\ \\ \tt \longmapsto - 3x - 19 = 30 \\ \\ \tt \longmapsto 3x + 19 = - 30 \\ \\ \tt \longmapsto 3x = - 30 -19 \\ \\ \tt \longmapsto 3x = - 49 \\ \\ \tt \longmapsto x = - \frac{49}{3}$

Answer 2

Answer:

Step-by-step explanation:

2x + 15 + 7 - 8x + 3x - 41 = 30

2x  - 8x + 3x + 15 + 7 - 41 = 30

Combine like terms

-3x - 19 = 30

Add 19 to both sides

-3x = 30 + 19

-3x = 49

Divide both sides by (-3)

x = 49/-3

x = -$16\frac{1}{3}$