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VMariaS [17]
2 years ago
9

Find the area of a triangle that has a 10cm side and angle of 105 and another side of 13 cm

Mathematics
1 answer:
bazaltina [42]2 years ago
6 0

Answer:

62.79cm

Step-by-step explanation:

<u>We are using TRIGONOMETRY</u>. To find the area of a triangle with 2 lengths and a non-right angle, we will use the sine rule.

Area of Triangle = 1/2 * a * b * sin(c)

(Where a & b represent our lengths, and sin(c) represents our angle.)

Area of Triangle = 1/2 * 10 * 13 * sin(105)

Area of the Triangle = 62.79cm

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A certain insecticide kills 60% of all insects in laboratory experiments. A sample of 12 insects is exposed to the insecticide i
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The probability that exactly 10 insects will die

                     P( X = 10 ) = 0.06385        

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given a certain insecticide kills 60% of all insects in laboratory experiments

Given proportion  p = 0.60

                           q = 1 - 0.60 = 0.40

Given sample size 'n' = 12

<u><em>Step(ii):</em></u>-

Let "X' be the random variable of binomial distribution

                              P(X=r) = n_{C_{r} } p^{r} q^{n-r}

The probability that exactly 10 insects will die

                              P(X=10) = 12_{C_{10} } (0.60)^{10} (0.40)^{12-10}

                           

                          n_{C_{r} } = \frac{n!}{(n-r)!r!} = \frac{12!}{(12-10)!10!} = 66

                          P(X=10) = 66 X (0.60)^{10} (0.40)^{2} = 0.06385

<u><em>Final answer:</em></u>-

The probability that exactly 10 insects will die

                     P( X = 10 ) = 0.06385        

4 0
3 years ago
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