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Oliga [24]
3 years ago
5

Please help in maths all answers.....2i/3-6i

Mathematics
2 answers:
pishuonlain [190]3 years ago
5 0

Answer: 45 degrees I think


Step-by-step explanation:


Crank3 years ago
3 0
2i / 3-6i

Multiply the top and bottom by the conjugate of 3-6i.

The conjugate is 3+6i

2i(3+6i). Foil = 6i + 12i^2. Or 6i -12 because i^2= -1

(3-6i)(3+6i). Foil. = 9- 36i^2

6i-12 / 9+36
6i-12 / 45
Divide each term by 3

Answer: 2i -4 / 15
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Between-group design compares two groups (randomly formed) on the same task, such as movement speed.

Given things that there are two groups that are randomly formed for the same task.

A between-group design in experimental design is an experiment in which two or more groups of individuals are assessed simultaneously by separate testing factors. This design is typically used instead of, or in conjunction with, the within-subject design, which applies identical modifications of circumstances to each participant in order to monitor the reactions.

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2 years ago
Solve for y 31=2y-5
DIA [1.3K]

31=2y-5

Add 5 on both -5+5 which cancels out and 31+5 which is 36 and then divide 36 by 2 which equals to 18.

So y=18 hope this helped (':


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Indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (4, 1) and
jenyasd209 [6]

Equation of a line is x+3y =-3.

<h3>What is a perpendicular bisector of the line segment?</h3>

A perpendicular bisector is a line that cuts a line segment connecting two points exactly in half at a 90 degree angle. To find the perpendicular bisector of two points, all you need to do is find their midpoint and negative reciprocal, and plug these answers into the equation for a line in slope-intercept form.

Given that,

Endpoints of the line segment are (x_{1},y_{1}) = (4, 1) and (x_{2},y_{2}) = (2, -5).

First find the midpoints of the given line segment.

M = \left(\frac{x_{1}+x_{2}  }{2},\frac{y_{1}+y_{2}  }{2}\Right)

    =  \left(\frac{4+2  }{2},\frac{1-5  }{2}\Right)

M   =  (3,-2)

Now, Find the slope of the line :

It is perpendicular to the line with (4,1) and (2,-5)

Slope between (x_{1},y_{1}) and (x_{2},y_{2}) = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

so,

the slope between (4,1) and (2,-5)  =  \frac{-5-1  }{2-4 }

                                                         = 3

perpendicular lines have slopes the multiply to get -1

3 times m=-1

m= \frac{-1}{3}

The equation of a line that has a slope of m and passes through the midpoints M(3,-2)  is

y-y_{1} =m(x-x_{1} )

y-(-2) =\frac{-1}{3} (x-3 )

(y+2) =\frac{-1}{3} (x-3 )

if we want slope intercept form

(y+2) =\frac{-1}{3} x+1

y= \frac{-1}{3} x-1

If we want standard form

\frac{1}{3} x+y = -1

x+3y =-3

Hence, Equation of a line is x+3y =-3.

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7 0
1 year ago
Find the coordinates of the turning point for the equation of the graph below y=x^2+14x+45
USPshnik [31]

Answer:

(- 7, - 4 )

Step-by-step explanation:

Given a quadratic in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the turning point is

x = - \frac{b}{2a}

y = x² + 14x + 45 ← is in standard form

with a = 1, b = 14 , then

x = - \frac{14}{2} = - 7

Substitute x = - 7 into the equation and evaluate for y

y = (- 7)² + 14(- 7) + 45 = 49 - 98 + 45 = - 4

coordinates of turning point = (- 7, - 4 )

4 0
3 years ago
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