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2 years ago

Copy the table below onto your paper. Complete it then write an equation that relates x and y.

Mathematics

1 answer:

IRISSAK [1]2 years ago

5 0

The equation is y = x - 3. just subtract 3 to get all of the blank spots.

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Find the quotient.<br><br> 35.4 ÷ 0.59

AleksandrR [38]

Answer:

35.4÷ 0.59=60

Step-by-step explanation:

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3 years ago

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Answer:

h=12

Step-by-step explanation:

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2 years ago

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anastassius [24]

Answer:

I would help you

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3 years ago

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Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How

HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that $\mu = 5.2r$ , in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

$P(X \geq 1) = 1 - P(X = 0) = 0.99$

Thus:

$P(X = 0) = 1 - 0.99 = 0.01$

We have that:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}$

Then

$e^{-5.2r} = 0.01$

$\ln{e^{-5.2r}} = \ln{0.01}$

$-5.2r = \ln{0.01}$

$r = -\frac{\ln{0.01}}{5.2}$

$r = 0.89$

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

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2 years ago

Use Midpoint and Slope Formulas to complete the tables below.1. Find the midpoint of RP, given the coordinates R (5, 8) and P (3

poizon [28]

The midpoint formula for a segment is:

$x_m,y_{_m}=\frac{(x_1+x_2)}{2},\frac{(y_1+y_2)}{2}$

apply to points R and P

$\begin{gathered} x_m,y_m=\frac{(5+3)}{2},\frac{(8+6)}{2} \\ x_m,y_m=\frac{8}{2},\frac{14}{2} \\ x_m,y_m=(4,7) \end{gathered}$

using the definition of slope find the slope of the segment

$m=\frac{y_2-y_1}{x_2-x_1}$

apply to points R and P

$\begin{gathered} m=\frac{8-6}{5-3} \\ m=\frac{2}{2} \\ m=1 \end{gathered}$

to lines are parallel when the slopes are the same

$\mleft\Vert m=1\mright?$

two lines are perpendicular when the product of the slopes is equal to -1

$\begin{gathered} m\cdot\perp m=-1 \\ 1\cdot\perp m=-1 \\ \perp m=-\frac{1}{1} \\ \perp m=-1 \end{gathered}$

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1 year ago