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bogdanovich [222]
3 years ago
14

Copy the table below onto your paper. Complete it then write an equation that relates x and y.

Mathematics
1 answer:
IRISSAK [1]3 years ago
5 0
The equation is y = x - 3. just subtract 3 to get all of the blank spots.
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What is the recursive rule for the following sequence: -9, -2, 5, 12, ….
tino4ka555 [31]

Answer:

The answer is option (C)=an-1+7

Step-by-step explanation:

A recursive rule is a formula that in which each term is expressed as a function of its preceding term(s), meaning in order to get to the nth term you have to express it in a form of the term that comes before it. In our case the a(n-1) term

So for the sequence -9, -2, 5, 12

The nth term is any number on the sequence and

  • -2 is the a(n-1) term for -9
  • 5 is the a(n-1) term for -2
  • 12 is the a(n-1) term for 5

So we need to find out what we have to do to the preceding term to get the next.

To get -2 from -9 we have to add 7 to -9; -9+7=-2

To get 5 from -2 we have to add 7 to -2; -2+7=5

To get 12 from 5 we add 7 to 5; 7+5=12

So the recursive rule would be= a n-1+7

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3 years ago
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harkovskaia [24]

Answer:

24 miles per hour.

Step-by-step explanation:

you divide 144 by 6 to get 24.

5 0
2 years ago
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wolverine [178]

Answer:

SUre

Step-by-step explanation:

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2 years ago
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1. Which equation can you use to find the value of x?
Alika [10]

Answer:

It's a proportion.

2 is to x as 15 is to 9, or 2/x = 15/9.

Multiply the means and extremes

15x = 18

divide both sides by 15 to get x by itself.

x = 1.2

Step-by-step explanation:

6 0
2 years ago
The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78
____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

m-t_{a/2,n-1}\frac{s}{\sqrt{n} } ≤ μ ≤ m+t_{a/2,n-1}\frac{s}{\sqrt{n} }

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and t_{a/2,n-1} is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and t_{0.05,9} by 1.8331, we get that the 90% confidence interval for the mean speed is:

74.2-(1.8331)\frac{5.3083}{\sqrt{10} } ≤ μ ≤ 74.2+(1.8331)\frac{5.3083}{\sqrt{10} }

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0
2 years ago
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