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Sati [7]
3 years ago
13

The ordered pairs (6, 8), (9,12),(x, 20),(18,y) represent a proportional relationship. find the value of x and y. (choose two an

swers)
a. x=8
b. x=12
c. x=15

a. y=21
b. y=24
c. y=28
Mathematics
1 answer:
Reil [10]3 years ago
8 0

Answer:

  • We have two points so let's use them effectively
  • We know that the x changes by 3 and the y changes by 4
  • Hence to get to y=20 we moved 2 times (8 units) so it's 9+ 3 + 3= 15
  • So x= 15
  • Now for y We have an x= 18, from 9 we moved 9 units of 3 total intervals: 4+4+4+12= 24
  • y=24
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using point (1,-4)
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The graph below describes the journey of a train between two cities.
Veseljchak [2.6K]

Answer:

[A] Acceleration in first 15 min = 200  km/h²

[B] Distance between two cities = 125 km

[C] Average Speed of journey =  62.5  km/hr

Step-by-step explanation:

To Solve:

Acceleration in first 15 min

Distance between two cities  

Average speed of journey

Solve:

[A] Work out the acceleration, in km/h?, in the first 15 mins.

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time                     Velocity  km/hr

0 Min  ( 0 hr)            0

15 Min (1/4 hr)           50

45 Min (3/4 hr)         50

60 MIn  ( 1 hr)            100

90 Min  ( 3/2 hr)        100

120 Min ( 2hr)            0

Acceleration in first 15 min  (1/4 hr)  =  (50 - 0)/(1/4 - 0)  = 50/(1/4)

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Hence, Answer for [A] = 200  km/h²

[B] Work out the distance between the two cities. $60 Velocity (in km/h)

= (1/2)(0 + 50)(1/4 - 0)  + 50 * (3/4 - 1/4)  + (1/2)(50 + 100)(1 - 3/4)  + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

=  25/4  + 25 + 75/4   + 50 + 25

= 125

Distance between two cities = 125 km

[C] Work out the average speed of the train during 20 the journey.

Average Speed of journey = 125/2  = 62.5  km/hr

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