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podryga [215]
3 years ago
15

consider a dianmeter of 8 feet and height of h feet.which equation can be used to find v,the volumeof the cylinder in cubic feet

Mathematics
1 answer:
yarga [219]3 years ago
4 0

Answer:

diameter times height times x = volume

Step-by-step explanation:

using the length times width times height equation for volume.

good luck :)

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Z-16z=15 what is z please
anygoal [31]

Answer:

z is equal to -0.88235294117

Step-by-step explanation:

so you first need to do is z minus 16z which is -17z.

you now have -17z is 15

you need to divide each side by -17z

so -17z divided by -17 is 1 z

and 15 divided by -17 is -0.88235294117

so z is equal to -0.88235294117

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2 years ago
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DO THESE ON A PIECE OF PAPER! PLEASE HELP! QUICK!!DO ALL OF THEM!!!
o-na [289]

Answer:

A.) 93

B.) 77

C.) 369

Step-by-step explanation:

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o paint a house, two painters are hired. The first painter can paint the entire house in ten hours. The second painter will need
alexandr1967 [171]
11+6=17 17÷2= 8.5 hours so the answer would be 4:50pm. Maybe
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2 years ago
Rotate shape A 90° clockwise with centre of rotation (0,0).
Andreyy89

Answer:

(2,4)====(-4,2)

(4,3)===(-3,4)

(2,3)====(-3,2)

5 0
2 years ago
A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar
ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let \mu = <u><em>mean waiting time for bus number 14.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 10 minutes      {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, H_A : \mu < 10 minutes    {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 7.8 minutes

             s = sample standard deviation = 2.5 minutes

             n = sample of different occasions = 18

So, <u><em>test statistics</em></u> =  \frac{7.8-10}{\frac{2.5}{\sqrt{18} } }  ~ t_1_7

                              =  -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0
3 years ago
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