8 5/12 because you have to get the 3 fractions denomenators to be the same. so 3, 4 and 2 all go into 12 then you need go multiply the top by the same number as the bottom
Answer:
210
Step-by-step explanation:
Here comes the problem from Combination.
We are being asked to find the number of ways out in which 3 students may sit on 7 seats in a row. Please see that in this case the even can not be repeated.
Let us start with the student one. For him all the 7 seats are available to sit. Hence number of ways for him to sit = 7
Let us see the student second. For him there are only 6 seats available to sit as one seat has already been occupied. Hence number of ways for him to sit = 6
Let us see the student third. For him there are only 5 seats available to sit as two seat has already been occupied. Hence number of ways for him to sit = 5
Hence the total number of ways for three students to be seated will be
7 x 6 x 5
=210
You would multiply it by 4
4(3x^2 +2 )
12x^2 +8
The equation of a cirecle with radius r and center at (h,k) is
(x-h)^2+(y-k)^2=r^2
r=10
center=(-2,-4)
(x+2)^2+(y+4)^2=10^2
(x+2)^2+(y+4)^2=100
(x,y)
sub given points (or use TI) and see if you get a true statmeent
A is on it
answer is A
