Answer:
The probability that such a driver will be involved in an accident during the first seventy-five days of the year is 0.408
Step-by-step explanation:
Consider the provide information.
The probability that such a driver will be involved in an accident in the first forty days is 0.25.
Therefore,
Where is X represents the random variable that shows time between beginning of a year and an accident.
X is the exponential distribution with λ as a parameter.
Therefore,
Now we want the probability that a driver will be involved in an accident during the first seventy five days.
Hence, the probability that such a driver will be involved in an accident during the first seventy-five days of the year is 0.408
Answer:
That is 7.
Step-by-step explanation:
112 = 2*2*2*2*7
So the smallest number is 7.
2*2*2*2*7*7 is a square number.
Answer:
First you add all of the results together for a sum of 243. Then, you divide that sum, 243 by 10, the number of results in total. That means the average weight of 10 random raccoons out of 150 raccoons in that wildlife preserve, is 24.3 pounds. Her statement is not reasonable because Jean stated the average weight of ALL raccoons is 25 pounds.
Step-by-step explanation:
hope this helps :)
Cot(t)= cos(t) / sin(t)
Cos(t) = sqrt(1 - sin^2(t) ) But this is in quad 4, so sin(t) <0
cot(t) = sqrt(1 -sin^2(t)) / - sint(t)
cot(t) = - sqrt( 1 - sin^2(t) ) / sin(t)
Like into a percentage or?