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3 years ago

A dvd is marked down 15% the regular price is $12 what is the sale price?

Mathematics

2 answers:

Makovka662 [10]3 years ago

7 0

The answer to this question is 1.79 but if you round up it should be 1.80

mash [69]3 years ago

4 0

15% off means the dvd is selling for 85% of the original price ( 100% - 15%=85%)

Multiply the original price by 85%

12 x 0.85 = 10.20

The price is $10.20

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Sam invests $800 at 6%/a compounded annually for 5 years. What is the total interest<br> earned?

s2008m [1.1K]

<h3>Answer: 270.58 dollars</h3>

======================================================

Work Shown:

A = account value after t years
P = principal or amount deposited = 800
r = interest rate in decimal form = 0.06
n = number of times we compound per year = 1
t = number of years = 5

So,

A = P*(1+r/n)^(n*t)

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2 years ago

In a simple regression analysis for a given data set, if the null hypothesis β = 0 is rejected, then the null hypothesis ρ = 0 i

kati45 [8]

Answer:

Null hypothesis: $\rho =0$

Alternative hypothesis: $\rho \neq 0$

The statistic to check the hypothesis is given by:

$t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}$

And is distributed with n-2 degrees of freedom

And the statistic to check the significance of a coeffcient in a regression is given by:

$t_1 = \frac{\hat{\beta_1} -0}{S.E (\hat{\beta_1})}$

For this case is importantto remember that t1 and p value for test of slope coefficient is the same test statistic and p value for the correlation test so then the answer would be:

Always

Step-by-step explanation:

In order to test the hypothesis if the correlation coefficient it's significant we have the following hypothesis:

Null hypothesis: $\rho =0$

Alternative hypothesis: $\rho \neq 0$

The statistic to check the hypothesis is given by:

$t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}$

And is distributed with n-2 degrees of freedom

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For this case is importantto remember that t1 and p value for test of slope coefficient is the same test statistic and p value for the correlation test so then the answer would be:

Always

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