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Volgvan
3 years ago
8

Convert thie following percent to a decimal: 80% 80.2 8.5 0.805 0.802 801.2

Mathematics
1 answer:
Masteriza [31]3 years ago
5 0

Answer:

Step-by-step explanation:

It would be 80.5, but that doesn't seem to be an option.

There may have perhaps been some sort of error?

You might be interested in
-8+9+5z+7x uses z=3 and x=5
forsale [732]
Just substitute their values into the expression:
= -8 + 9 + 5z + 7x
= -8 + 9 + 5(3) + 7(5)
= 1 + 15 + 35
= 51

In short, Your Answer would be 51

Hope this helps!
4 0
3 years ago
Read 2 more answers
How much of a 14% iodine solution should be added to 89 ounces of a 47% iodine solution to get a 29% solution
Elza [17]
Whatever% of anything is just (whatever/100) * anything.

x = ounces of 14% iodine.

y = ounces of 29% iodine.

we know that in a 14% iodine solution, 14% is iodine and the rest is something else, we also know that "x" ounces of the solution have 14% of iodine, how much is that?  (14/100) * x, or 0.14x.

likewise, in the 89 ounces of 47% solution there is (47/100) * 89 of iodine.

and likewise as well, in "y" ounces of 29% iodine there is (29/100) * y, or 0.29y of iodine.

bearing in mind that, whatever "x" and "y" may be, x + 89 = y, and that the sum of the iodine amounts also will equate 0.29y.

\bf \begin{array}{lccclll}
&\stackrel{ounces}{amount}&\stackrel{\%~of~iodine}{quantity}&\stackrel{iodine~oz}{amount}\\
&------&------&------\\
\textit{14\% solution}&x&0.14&0.14x\\
\textit{47\% solution}&89&0.47&41.83\\
------&------&------&------\\
mixture&y&0.29&0.29y
\end{array}
\\\\\\
\begin{cases}
x+89=\boxed{y}\\
0.14x+41.83=0.29y\\
--------------\\
0.14x+41.83=0.29\left( \boxed{x+89} \right)
\end{cases}
\\\\\\
0.14x+41.83=0.29x+25.81\implies 16.02=0.15x
\\\\\\
\cfrac{16.02}{0.15}=x\implies 106.8=x
6 0
3 years ago
21g = 84<br><br> A. g = 3<br><br> B. g = 4<br><br> C. g = 5
natta225 [31]
21g=84
g=84/21
g=4

The answer is B
6 0
3 years ago
Read 2 more answers
Given P(E) = 0.15, what is P(E')?
UkoKoshka [18]

Answer:

0.85

Step-by-step explanation:

P(E)+P(E')=1

SO, P(E')=1-P(E)

OR,P(E')=1-0.15

PLEASE MARK MY ANSWER AS BRAINLIEST.

= 0.85

6 0
2 years ago
Forma de distribución del resultado obtenido por los componentes de una sociedad tomando en cuenta dos factores que intervienen,
Naddik [55]
Reparto proporcional
4 0
3 years ago
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