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2 years ago

Simplify 10 to the power of 0

Mathematics

2 answers:

OverLord2011 [107]2 years ago

5 0

Answer:

Step-by-step explanation:

mash [69]2 years ago

3 0

Answer:

Step-by-step explanation:

Anything to the power of 0 is 1

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PLEASE HELP ASAP!!! WILL GIVE BRAINLIEST FOR BEST/RIGHT ANSWER!!!!!!!!

Nesterboy [21]

The answer is A, please mark brainliest.

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2 years ago

Read 2 more answers

Explain how to write 5/3 as a product of a whoke number and a unit fraction

KIM [24]

Answer:

1 $\frac{2}{3\\}$

Step-by-step explanation:

5/3 = 3/3 * 2/3

3/3 = 1

So the answer is 1 $\frac{2}{3\\}$

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3 years ago

Work out the volume of the shape

pashok25 [27]

Answer:

$\large\boxed{V=\dfrac{1,421\pi}{3}\ cm^3}$

Step-by-step explanation:

We have the cone and the half-sphere.

The formula of a volume of a cone:

$V_c=\dfrac{1}{3}\pi r^2H$

r - radius

H - height

We have r = 7cm and H = (22-7)cm=15cm. Substitute:

$V_c=\dfrac{1}{3}\pi(7^2)(15)=\dfrac{1}{3}\pi(49)(15)=\dfrac{735\pi}{3}\ cm^3$

The formula of a volume of a sphere:

$V_s=\dfrac{4}{3}\pi R^3$

R - radius

Therefore the formula of a volume of a half-sphere:

$V_{hs}=\dfrac{1}{2}\cdot\dfrac{4}{3}\pi R^3=\dfrac{2}{3}\pi R^3$

We have R = 7cm. Substitute:

$V_{hs}=\dfrac{2}{3}\pi(7^3)=\dfrac{2}{3}\pi(343)=\dfrac{686\pi}{3}\ cm^3$

The volume of the given shape:

$V=V_c+V_{hs}$

Substitute:

$V=\dfrac{735\pi}{3}+\dfrac{686\pi}{3}=\dfrac{1,421\pi}{3}\ cm^3$

7 0

2 years ago

The coordinates of Trapezoid EFGH are E(8, 8), F(8,10), G(1, 6), and H(4, 1). The image of EFGH under dilation is E’F’G’H’.

Sergeu [11.5K]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

Below are the choices:

A) (2, 6)
B) (4, 6) 
C) (2, 5) 
D) (4, 5)

The answer should be: (4, 5)
E = (8, 8) -----> E' = (4, 4) = (8/2, 8/2)
F = (8, 10) -----> F' = (8/2, 10/2) = (4, 5)

5 0

2 years ago

When a force of 30 N acts on a certain object the acceleration of the object is 5m/s2 if the force is changed to 54 N what will

PtichkaEL [24]

Answer:

The correct answer is 9 m per $second^{2}$

Step-by-step explanation:

Force is defined by mass of an object times it's acceleration.

Let the mass of the object be m kilograms.

When a force of 30 N acts on a certain object the acceleration of the object is 5 m per $second^{2}$

∴ 30 = m × 5

⇒ m = 6.

If the force is changed to 54 N, let the acceleration of the object be x m per $second^{2}$ .

∴ 54 = m × x

⇒ x = $\frac{54}{6}$ = 9

Thus when the force is 54 N, the acceleration of the object is 9 m per $second^{2}$ .

6 0

3 years ago