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Sophie [7]
3 years ago
14

Jose wants to find the perimeter of triangle ABC. He uses the distance formula to determine the length of AC. Finish Jose’s calc

ulations to find the length of AC.
What is the perimeter of triangle ABC? Round the answer to the nearest tenth, if necessary.

12.0 units
12.4 units
15.0 units
15.4 units
Mark this and return
Mathematics
1 answer:
AleksAgata [21]3 years ago
8 0
The answer is 15 units
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55% of 70 round to the nearest tenth
Verizon [17]
70 * 55/100=38.5

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Every time I use a piece of scrap paper, I crumple it up and try to shoot it inside the recycling bin across the room. I'm prett
valentinak56 [21]

Using the binomial distribution, it is found that there is a 0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

With 5 shoots, the probability of making at least one is \frac{211}{243}, hence the probability of making none, P(X = 0), is \frac{232}{243}, hence:

(1 - p)^5 = \frac{232}{243}

\sqrt[5]{(1 - p)^5} = \sqrt[5]{\frac{232}{243}}

1 - p = 0.9908

p = 0.0092

Then, with 6 shoots, the parameters are:

n = 6, p = 0.0092.

The probability that at least two of them make it inside the recycling bin is:

P(X \geq 2) = 1 - P(X < 2)

In which:

[P(X < 2) = P(X = 0) + P(X = 1)

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.0092)^{0}.(0.9908)^{6} = 0.9461

P(X = 1) = C_{6,1}.(0.0092)^{1}.(0.9908)^{5} = 0.0527

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.9461 + 0.0527 = 0.9988

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9988 = 0.0012

0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

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2 years ago
Graph a line with a slope of -2/5 that contains the point (-3, 5)
ValentinkaMS [17]
Picture so I am able to solve problem please
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3 years ago
If the second number is subtracted from the sum of the first number and 2 times the third number, the result is 1. The thrid num
weeeeeb [17]

Answer:

<h2>x = 0, y = 5, z = 3</h2>

Step-by-step explanation:

x,\ y,\ z-\text{three numbers}\\\\\left\{\begin{array}{ccc}(x+2z)-y=1&(1)\\z+2x=3&(2)\\x+3y+z=18&(3)\end{array}\right\\\\(2)\\z+2x=3\qquad\text{subtract}\ 2x\ \text{from both sides}\\z=3-2x\qquad(*)\\\\\text{Substitute}\ (*)\ \text{to (1) and (3)}\\\\\left\{\begin{array}{ccc}x+2(3-2x)-y=1&\text{use the distributive property}\\x+3y+(3-2x)=18\end{array}\right

\left\{\begin{array}{ccc}x+(2)(3)+(2)(-2x)-y=1\\x+3y+3-2x=18&\text{subtract 3 from both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+6-4x-y=1&\text{subtract 6 from both sides}\\(x-2x)+3y=15\end{array}\right\\\left\{\begin{array}{ccc}(x-4x)-y=-5\\-x+3y=15\end{array}\right\\\left\{\begin{array}{ccc}-3x-y=-5&\text{multiply both sides by 3}\\-x+3y=15\end{array}\right

\underline{+\left\{\begin{array}{ccc}-9x-3y=-15\\-x+3y=15\end{array}\right}\qquad\text{add all sides of the equations}\\.\qquad-10x=0\qquad\text{divide both sides by (-10)}\\.\qquad\boxed{x=0}\\\\\text{Put it to the second equation:}\\-0+3y=15\\3y=15\qquad\text{divide both sides by 3}\\\boxed{y=5}\\\\\text{Put the value of}\ x\ \text{to}\ (*):\\\\z=3-2(0)\\\boxed{z=3}

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Simplify (7)(-6). <br> a) -42<br> b) -13 <br> c) 1<br> d)42
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It’s A) simplify it you’ll get -42 because a negative times a positive is an negative
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