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malfutka [58]
3 years ago
6

-3y - 12< -6

Mathematics
2 answers:
frosja888 [35]3 years ago
6 0

Answer:

y>-2

Step-by-step explanation:

-3y-12<-6 (move the constant to the right)

-3y<-6+12 (calculate)

-3y<6 (divide both sides)

solution: y>-2

hope this helps!

weeeeeb [17]3 years ago
3 0

Answer:

y>2

Step-by-step explanation:

-3y-12<-6

-3y<6

y>2

I hope this answer helped, and if it was correct, please mark this as brainliest! Thank you!

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What is the area of the following trapezoid 210 280 420 140
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Answer:

Step-by-step explanation:

A=  a+b/2 h (area = a +b over 2 times H) plug in your numbers

I dont have a picture, if i did i could solve it, but here is the formula

     

3 0
3 years ago
Elena went on a 6-mile walk. She completed the first half of the walk 1 mi/h faster than usual and the second half of the walk 2
xxTIMURxx [149]

Answer:

Her usual rate is 0.8333 miles per hour.

Step-by-step explanation:

The velocity formula is given by:

v = \frac{d}{t}

In which d is the distance and t is the time.

She completed the first half of the walk 1 mi/h faster than usual

Her usual rate is v. 1mph faster is v + 1.

The second half of the walk 2 mi/h slower than the first half.

The first half is v + 1.

2mph slower is v + 1 - 2 = v - 1. Then

Total rate:

7.2 hours, and 6 miles. So

One half is v+1 and the other is v - 1. This is why each is multiplied by 0.5.

0.5(v + 1) + 0.5(v - 1) = \frac{6}{7.2}

0.5v + 0.5 + 0.5v - 0.5 = 0.8333

v = 0.8333

Her usual rate is 0.8333 miles per hour.

8 0
3 years ago
√5+√6 plsssssssssssssssssssssssssssse​
pantera1 [17]

Answer:

4,68556

Step-by-step explanation:

√5+√6

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8 0
3 years ago
Read 2 more answers
Find an equation of the circle that has center (-4,3) and passes through (6,-4).
kumpel [21]

Answer:

(x+4)^2+(y-3)^2=149

Step-by-step explanation:

The equation of a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center of the circle and r is the radius of the circle.

Given that (h,k)\rightarrow(-4,3) and it passes (6,-4), their distance between each other must the radius of the circle, so we can use the distance formula to find the radius:

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\\\d=\sqrt{(-4-3)^2+(6-(-4))^2}\\\\d=\sqrt{(-7)^2+10^2}\\\\d=\sqrt{49+100}\\\\d=\sqrt{149}

Therefore, if the length of the radius is r=\sqrt{149} units, then r^2=149, making the final equation of the circle (x+4)^2+(y-3)^2=149

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