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xenn [34]
4 years ago
10

How many excess electrons must you add to an object to give it a charge of -6.50 μc?

Chemistry
1 answer:
xenn [34]4 years ago
5 0
Micro = 10^-6 
<span>n = nano = 10^-9 </span>

<span>(a) -2.5 micro coulombs = -2.5 X 10^-6 </span>
<span>The charge on a electron is always -1.60 X 10^-19. </span>

<span>So, given charge divided by charge on electron gives you number of electrons. </span>
<span>(-2.5X10^-6)/(-1.60X10^-19) = 1.5625 X 10^13 excess electrons. </span>

<span>(b) -2.5 nano coulombs = -2.5 X 10^-9 </span>
<span>The charge on a electron is always -1.60 X 10^-19. </span>

<span>So, given charge divided by charge on electron gives you number of electrons. </span>
<span>(-2.5X10^-9)/(-1.60X10^-19) = 1.5625 X 10^10 excess electrons. </span>

<span>Round my answers to 3 significant figures if needed or to the appropriate form asked by the question.</span>
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A silver bar has a mass of 368g. What is the volume in cm³ of the bar? The density of silver is 19.5g/cm³.
BabaBlast [244]

Answer:

<h2>18.87 cm³</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question we have

volume =  \frac{368}{19.5}   \\  = 18.871794..

We have the final answer as

<h3>18.87 cm³</h3>

Hope this helps you

4 0
3 years ago
A disadvantage of sexual reproduction is that
sineoko [7]
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8 0
3 years ago
What is the most mass of (NH4)2CO3 (H=1,C=12,N=14,O=16
Agata [3.3K]

Answer:

96.09 g/mol

Explanation:

You just need to first get the atomic weights of the elements involved. You can easily get these from your periodic table.

If you are going to do this properly, please use the weight with at least two decimal places for accuracy (e.g. 15.99 g/mol).

Also, please take note that I will be using the unit g/mol for all the weights. Thus,

Step 1

N = 14.01 g/mol

H = 1.008 g/mol

O = 16.00 g/mol

C = 12.01 g/mol

Since your compound is  

(

N

H

4

)

2

C

O

3

, you need to multiply the atomic weights by their subscripts. Therefore,

Step 2

N = 14.01 g/mol × 2 =

28.02 g/mol

H = 1.008 g/mol × (4×2) =

8.064 g/mol

 

O = 16.00 g/mol × 3 =

48.00 g/mol

C = 12.01 g/mol × 1 =

12.00 g/mol

To get the mass of the substance, we need to add all the weights from Step 2.

Step 3

molar mass of

(

NH

4

)

2

CO

3

=

(28.02 + 8.064 + 48.00 + 12.01) g/mol

=

96.09 g/mol

this is a google search and a example i hope is helps to solve

6 0
3 years ago
A bowling ball is pushed with a force of 22.0 N and accelerates at 5.5m/s. What is the mass of the bowling ball
Luden [163]
Hello!

Data:

F (force) = 22.0 N
m (mass) = ? (in Kg)
a (acceleration) = 5.5 m/s²

We apply the data to the Resultant Force formula, we have:

F =m*a

22 = m*5.5

5.5 m = 22

m =  \dfrac{22}{5.5}

\boxed{\boxed{m = 4\:Kg}}\end{array}}\qquad\checkmark

I hope this helps. =)
7 0
3 years ago
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How do the structures of particles in substances vary?
lesya692 [45]

Answer:

56

Explanation:

8 0
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