Answer:
a. 4 sig figs
b. 3 sig figs
c. 2 sig figs
Answer:
B 1.23 g/cc
Explanation:
For something to float on seawater, the density must be less than 1.03 g/mL. If the object sinks, the density is greater than 1.03 g/mL.
Let’s examine the answer choices. Keep in mind, the ice berg is mostly below the water level.
A. 0.88 g/cc
This is less than 1.03 g/cc, which would result in floating.
B. 1.23 g/cc
This is the best answer choice. The iceberg is mostly beneath the water, but some of it is exposed. The density is greater than 1.03 g/mL, but not so much greater that it would immediately sink.
C. 0.23 g/cc
This is less than 1.03 g/cc, which would produce floating.
D. 4.14 g/cc
This is much greater than 1.03 g/cc and the result would be sinking.
20 drops in a milliliter :)
the volume of 2.5% m/v koh which can prepared from 125 ml of a 5% koh solution is calculated using the following formula
m1v1= m2 v2
M1= 5/100= 0.05
v1= 125
m2=2.5/100=0.025
V2=?
v2= m1v1/m2
=0.05 x125 /0.025=250 ml
