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3 years ago

12

Can a hypothesis be accurately tested by performing one experiment?

2 answers:

trasher [3.6K]3 years ago

6 0

When it comes to Explosions............its all 50---50

Levart [38]3 years ago

5 0

Depends on the thoroughness of that particular experiment. But just in general no, you usually need more than one experiment to verify a hypothesis.

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Narceine is a narcotic in opium that crystallizes from solution as a hydrate that contains 10.8 mass % water and has a molar mas

Leto [7]

Thewater of hydration x in narceine. xH₂O is 3

<h3>What is Water of Hydration?</h3>

In chemistry, water molecules found inside crystals are referred to as "water of crystallization" or "water of hydration." When crystals are formed from aqueous solutions, water is frequently included.
The entire mass of water in a substance at a specific temperature is sometimes referred to as water of hydration, and it is typically present in a stoichiometric ratio.
The term "water of crystallization" has historically been used to describe water that is not physically linked to the metal cation but is present in the crystalline structure of a metal complex or salt.
Many chemicals include water molecules in their crystalline structures when they crystallize from water or solvents that contain water. Heating a sample usually removes the water of crystallization, but the crystalline qualities are frequently lost.

Given that hydrate is 10.8% by mass

molar mass = 499.52 g/mol

calculating the amount of water

mass of water = $\dfrac{10.8 \times 499.5}{100}$

mass of water = 53.95 g

moles of water = $\dfrac{mass}{molar mass}$

moles of water = $\dfrac{53.95}{18}$ = 3

then the water of hydration x in narceine. xH₂O is 3

To learn more about water of hydration with the given link brainly.com/question/4355575

#SPJ4

7 0

1 year ago

An HCl solution has a concentration of 0.09714 M. Then 10.00 mL of this solution was then diluted to 250.00 mL in a volumetric f

cestrela7 [59]

Answer:

A. Concentration of diluted acid = 0.00389 M

B. Concentration of OH- in AgOH solution = 0.00012 M

Explanation:

A. Using the dilution formula: C1V1 = C2V2

Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

From the data provided, C1 = 0.09714 M, V1 = 10.0 mL, V2 = 250.0 mL and C2 = ?

Making C2 subject of the formula above; C2 = C1V1/V2

C2 = 0.09714 M × 10 / 250 = 0.00389 M

B. Equation of the neutralization reaction is given below:

HCl + AgOH ---> AgCl + H₂O

From the equation, 1 mole of acid neutralizes 1 mole of base

Using the titration formula; CaVa/CbVb = na/nb

Where Ca is the concentration of the acid HCl = 0.00389 M

Va is the volume of acid = 7.93 mL

Cb is the concentration of base, AgOH = ?

Vb is volume of base = 250.0 mL

na/nb = mole ratio of acid and base = 1

Making Cb subject of the formula in the equation above; Cb = CaVa/Vb

Cb = 0.00389 M × 7.93 / 250

Cb = 0.00012 M

7 0

3 years ago

What type of mixture contains the largest particles

tia_tia [17]

A suspension is the mixture with the largest particles.

6 0

3 years ago

What is the electron configuration of Lithium

9966 [12]

Answer:

[He] 2s1

Explanation:

8 0

4 years ago

What is the [OH-] in a solution that has a [H3O+] = 1.0 x 10-6 M?

nika2105 [10]

Answer:

explanation

$kw = 1 \times {10}^{ - 14}$

$oh = {?}$

$h3o = 1.0 \times 10 {}^{ - 6}$

formula

$kw = h3o \times oh$

$insert \: values$

$1.0 \times 10 {}^{ - 14} = 1.0 \times {10}^{ - 6} \times oh$

$\frac{1.0 \times 10 {}^{ - 14} }{ 1.0 \times 10 {}^{ - 6} } = oh$

$1 \times {10}^{ - 8}$

7 0

3 years ago