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2 years ago

There are 4 elephants in the preserve. Each elephant eats 2 1/4tons of vegetation in a week.

Mathematics

2 answers:

irinina [24]2 years ago

6 0

4 times 2 1/2 tons is 10 tons per week!

kiruha [24]2 years ago

3 0

Since there are 4 elephants, they would eat 2 1/2 tons multiplied by 4 each week.

So. Change 2 1/2 to an improper fraction. 5/2

Then multiply 5/2 by 4/1.

20/2

Then simplify.

10 tons a week is your answer.

Read more about statements at:

brainly.com/question/4344214

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5 0

2 years ago

Una persona pensó hacer una obra en 15 días; pero tardó 10

Ivenika [448]

Answer:

<em>Trabajó 3 horas al día</em>

Step-by-step explanation:

<u>Proporcionalidad</u>

Una persona planeó terminar la obra en 15 dias, pero tardó 10 dias adicionales porque trabajó 2 horas menos por día.

Usaremos proporciones para calcular las horas de trabajo diarias.

Si 2 horas diarias representan 10 dias de atraso, entonces cada hora representa 5 dias de trabajo.

Si la obra tardaba 15 dias, entonces la persona trabajó 15/5 = 3 horas diarias.

8 0

3 years ago

Pleaseeee pleaseee help mee with precal...One root of 2x2 + 8x + c = 0 is r1 = 1 + √5. Find r2.

igomit [66]

If a root is a+√b then another is a-√b because of quadatic formula

r2=1-√5

6 0

3 years ago

Read 2 more answers

Solve for x. Write both solution, separated by a comma. 4x^2-x-3=0.

Step2247 [10]

Answer:

x = -3/4, 1

Step-by-step explanation:

Factor left side of the equation.

(4x + 3)(x - 1) = 0

Set factors equal to 0.

4x + 3 = 0

4x = -3

x = -3/4

x - 1 = 0

x = 1

6 0

3 years ago

Read 2 more answers

Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ < 55 A sample of 36 is used. Identify the p-value and state your con

Ket [755]

Answer:

Step-by-step explanation:

Given that:

$H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55$

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }$

$Z = \dfrac{-1}{\dfrac{5.3}{6} }$

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

For x = 53 and s = 4.6

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }$

$Z = \dfrac{-2}{\dfrac{4.6}{6} }$

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

$Conclusion: \ There \ is \ sufficient \ evidence \ to \ conclude \ that$ $\mu < 55$

For x = 56 and s = 5.0

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }$

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

6 0

3 years ago