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polet [3.4K]
3 years ago
15

the formula y-y1 =m(x-x1) is the pot slope form of the equation of a line where m is the slope of the line and(x,y) and (x1,y1)

are points of the line. Solve the equation for m, and e slope of a line that6 includes the poits (4,-2) and (5,0).
Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
6 0
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~{{ 4}} &,&{{ -2}}~) 
%  (c,d)
&&(~{{ 5}} &,&{{ 0}}~)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{5-(-2)}{0-4}\implies \cfrac{5+2}{0-4}\implies -\cfrac{7}{4}

\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=-\cfrac{7}{4}(x-4)
\\\\\\
y+2=-\cfrac{7}{4}(x-4)\implies y+2=-\cfrac{7}{4}x+7\implies y=-\cfrac{7}{4}x+9
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Find the missing side.<br> Round to the nearest tenth.<br> For all 4 pics
Firlakuza [10]

Answer:

1st pic) 17.8

2nd pic) 16.8

3rd pic) 9.1

4th pic) 13.5

Step-by-step explanation:

<u>1st pic:</u> cos = \frac{adjacent}{hypothenuse}

(write equation) Cos 27 (cos 27 = 0.89) = \frac{x}{20}

(new equation) 0. 89 = \frac{x}{20}

(multiply 20 on both sides) 0.89 x 20 = \frac{x}{20} x 20

(solve) 17.8 = x

<u>2nd pic:</u> tan = \frac{adjacentx}{hypothenuse}

(write equation) tan 40 (tan 40 = 0.84) = \frac{32}{x}

(new equation) 0.84 =  \frac{32}{x}

(multiply 32 on both sides) 0.84 x 20 =  \frac{32}{x} x 20

(solve) 16.8 = x

<u>3rd pic:</u> cos = \frac{adjacent}{hypothenuse}

(write equation) cos 55 (cos 55 = 0.57) = \frac{16}{x}

(new equation) 0.57 = \frac{16}{x}

(multiply 16 on both sides) 0.57 x 16 = \frac{16}{x} x 16

(solve) 9.1 = x

<u>4th pic:</u> tan = \frac{adjacentx}{hypothenuse}

(write eqaution) tan 42 (tan 42 = 0.90) = \frac{x}{15}

(new equation) 0.90 = \frac{x}{15}

(multiply 15 on both sides) 0.90 x 15 = \frac{x}{15} x 15

(solve) 13.5 = x

4 0
3 years ago
1-What is the sum of the series? ​∑j=152j​ Enter your answer in the box.
tangare [24]

Answer:

Please see the Step-by-step explanation for the answers

Step-by-step explanation:

1)

∑\left \ {{5} \atop {j=1}} \right. 2j

The sum of series from j=1 to j=5 is:

∑ = 2(1) + 2(2) + 2(3) + 2(4) + 2(5)

  =  2 + 4 + 6 + 8 + 10

∑ = 30

2)

This question is not given clearly so i assume the following series that will give you an idea how to solve this:

∑\left \ {{4} \atop {k=1}} \right. 2k²

The sum of series from k=1 to j=4 is:

∑ = 2(1)² + 2(2)² + 2(3)² + 2(4)²

  = 2(1) + 2(4) + 2(9) + 2(16)

  =  2 + 8 + 18 + 32

∑ = 60

∑\left \ {{4} \atop {k=1}} \right. (2k)²

∑ = (2*1)² + (2*2)² + (2*3)² + (2*4)²

  = (2)² + (4)² + (6)² + (8)²

  = 4 + 16 + 36 + 64

∑ = 120

∑\left \ {{4} \atop {k=1}} \right. (2k)²- 4

∑ = (2*1)²-4 + (2*2)²-4 + (2*3)²-4 + (2*4)²-4

  = (2)²-4 + (4)²-4 + (6)²-4 + (8)²-4

  = (4-4) + (16-4) + (36-4) + (64-4)

  = 0 + 12 + 32 + 60

∑ = 104

∑\left \ {{4} \atop {k=1}} \right. 2k²- 4

∑ = 2(1)²-4 + 2(2)²-4 + 2(3)²-4 + 2(4)²-4

  = 2(1)-4 + 2(4)-4 + 2(9)-4 + 2(16)-4

  = (2-4) + (8-4) + (18-4) + (32-4)

  = -2 + 4 + 14 + 28

∑ = 44

3)

∑\left \ {{6} \atop {k=3}} \right. (2k-10)

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)  

  = (6-10) + (8-10) + (10-10) + (12-10)

  = -4 + -2 + 0 + 2  

∑ = -4

4)

1+1/2+1/4+1/8+1/16+1/32+1/64

This is a geometric sequence where first term is 1 and the common ratio is 1/2 So

a = 1

This can be derived as

1/2/1 = 1/2 * 1 = 1/2

1/4/1/2 = 1/4 * 2/1 = 1/2

1/8/1/4 = 1/8 * 4/1  = 1/2

1/16/1/8 = 1/16 * 8/1  = 1/2

1/32/1/16 = 1/32 * 16/1  = 1/2

1/64/1/32 = 1/64 * 32/1  = 1/2

Hence the common ratio is r = 1/2

So n-th term is:

ar^{n-1} = 1(\frac{1}{2})^{n-1}

So the answer that represents the series in sigma notation is:

∑\left \ {{7} \atop {j=1}} \right. (\frac{1}{2})^{j-1}

5)

−3+(−1)+1+3+5

This is an arithmetic sequence where the first term is -3 and the common difference is 2. So  

a = 1

This can be derived as

-1 - (-3) = -1 + 3 = 2

1 - (-1) = 1 + 1 = 2

3 - 1 = 2

5 - 3 = 2

Hence the common difference d = 2

The nth term is:

a + (n - 1) d

= -3 + (n−1)2

= -3 + 2(n−1)

= -3 + 2n - 2

= 2n - 5

So the answer that represents the series in sigma notation is:

∑\left \ {{5} \atop {j=1}} \right. (2j−5)

6 0
3 years ago
A person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen he sells it at Rs 80 a pair find the gain p
marusya05 [52]

Answer:

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Step-by-step explanation:

We need to calculate the <u>unit selling price and cost of each cosmetics.</u>

If a person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen., then for 1 cosmetics, we will say;

x = 1 cosmetic

since 360 = 12 cosmetic

cross multiply

12x = 360

x = 360/12

x = 30

Hence the unit cost price of the cosmetics will be Rs. 30

Similarly, if he sells it at Rs 80 a pair, then he sold one cosmetic at 80/2 = Rs. 40 (a pair is 2 cosmetics)

Selling price per unit = Rs. 40

Cost price per unit = Rs. 30

percent gain = SP-CP/CP * 100%

percent gain = 40-30/30 * 100

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Hence the percentage gain is 33.33%

5 0
3 years ago
2 25 divided by 11 10 in fraction
koban [17]

Answer:

\frac{4}{55}

Step-by-step explanation:

\frac{2}{25}  \div  \frac{11}{10}

\frac{2}{25}  \times  \frac{10}{11}

\frac{2}{5}  \times  \frac{2}{11}  =  \frac{2 \times 2}{5 \times 11}

\frac{4}{5 \times 11}

=  \frac{4}{55}

4 0
3 years ago
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Is 24/30 in simplest form
KatRina [158]
The answer to 24/30 in simplest form is 4/5
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