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erastovalidia [21]
3 years ago
9

Triangle ABC is transformed to obtain triangle A′B′C′:

Mathematics
1 answer:
Lisa [10]3 years ago
8 0

Answer:

Option C is right.

Step-by-step explanation:

Given is a graph with two triangles marked on it.

Triangle ABC is in the I quadrant with vertices (2,2) (2,10) and (8,12)

Triange A'B'C' is in the III quadrant with vertices (-1,-1), (-1,-5) and (-4,-6)

On comparison we find corresponding side of AB is A'B'

Length of AB = 8 and Length of A'B' = 4.

Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2.

Now since moved to III quadrant from I quadrant we find that there is a rotation of triangle ABC about the origin.  The degree of rotation is 180 degrees.

Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2 and then rotating it about the origin by 180 degrees

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Find the measures of the angles of a triangle if the measure of one angle is twice the measure of a second angle and the third a
guapka [62]

Answer:

<h2><em> 38°, 66° and 76°</em></h2>

Step-by-step explanation:

A triangle consists of 3 angles and sides. The sum of the angles in a triangle is 180°. Let the angle be <A, <B and <C.

<A + <B + <C = 180° ...... 1

If the measure of one angle is twice the measure of a second angle then

<A = 2<B ...... 2

Also if the third angle measures 3 times the second angle decreased by 48, this is expressed as <C = 3<B-48............ 3

Substituting equations 2 and 3 into 1 will give;

(2<B) + <B + (3<B-48) = 180°

6<B- 48 = 180°

add 48 to both sides

6<B-48+48 = 180+48

6<B = 228

<B = 228/6

<B =38°

To get the other angles of the triangle;

Since <A = 2<B  from equation 2;

<A = 2(38)

<A = 76°

Also <C = 3<B-48 from equation 3;

<C = 3(38)-48

<C = 114-48

<C = 66°

<em>Hence the measures of the angles of the triangle are 38°, 66° and 76°</em>

4 0
3 years ago
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