Triangle ABC is transformed to obtain triangle A′B′C′:

Mathematics

1 answer:

Lisa [10]3 years ago

8 0

Answer:

Option C is right.

Step-by-step explanation:

Given is a graph with two triangles marked on it.

Triangle ABC is in the I quadrant with vertices (2,2) (2,10) and (8,12)

Triange A'B'C' is in the III quadrant with vertices (-1,-1), (-1,-5) and (-4,-6)

On comparison we find corresponding side of AB is A'B'

Length of AB = 8 and Length of A'B' = 4.

Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2.

Now since moved to III quadrant from I quadrant we find that there is a rotation of triangle ABC about the origin. The degree of rotation is 180 degrees.

Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2 and then rotating it about the origin by 180 degrees

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A spinner has red, green, blue, and orange sections. The probability of landing on red is 2/3, on green is 1/12, on blue is 1/12

alexira [117]

Answer:

Step-by-step explanation:

P(landing on orange)=1 - [2/3 + 1/12 + 1/12]

$=1-[\frac{2}{3}+\frac{2}{12}]\\\\=1-[\frac{2}{3}+\frac{1}{6}]\\\\=1-[\frac{2*2}{3*2}+\frac{1}{6}]\\\\=1-[\frac{4}{6}+\frac{1}{6}]\\\\=1-[\frac{4+1}{6}]\\\\=1-\frac{5}{6}\\\\=\frac{6}{6}-\frac{5}{6}\\\\=\frac{1}{6}$