Answer:
37.68cm
Step-by-step explanation:
C = 2 
r
C = circumference
= the constant pi (3.14)
r = radius of the circle (6cm)
d = diameter of the circle (12cm)
d = 2r
C = 2 · 3.14 · 6
C = 37.68cm
1 cubic meter = 100 cm * 100 cm * 100 cm = 1 x 10^6 cc
1 kilogram = 1,000 grams
13.6 g / cc
If we had a cubic meter of mercury, its mass would be (or it would "weigh") 13.6 * 1,000,000 = 13,600,000 grams or 13,600 kilograms.
And so its density would be 13,600 kg / cubic meter.
Answer:
B. 5/6 of a number cannot be greater than the number.
7/3 = 2 1/3 > 1 2/3
Answer:
30m
Step-by-step explanation:
<em>Since we are not told what to look for, we can find the maximum height reached by the rocket</em>
Given the rocket's flight approximately modeled by the equation
h(t) = - 12t ^ 2 + 36t + 3
At maximum height dh/dt = 0
dh/dt = --24t + 36
0 = -24t + 36
24t = 36
t= 36/24
t = 1.5s
Get the max height
h(1.5) = - 12 (1.5)^ 2 + 36(1.5) + 3
h(1.5) = - 12(2.25) + 54 + 3
h(1.5) = -27 + 57
h(1.5) = 30m
Hence the maximum height reached by the rocket is 30m
