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elena55 [62]
3 years ago
13

Use the stem-and-leaf plot to answer the question.

Mathematics
2 answers:
Norma-Jean [14]3 years ago
7 0

Answer:

75

Step-by-step explanation:

mode is the most occurring number

dolphi86 [110]3 years ago
3 0

C 75 is the correct answer

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1/4 (8s + 16) help please
Tresset [83]

Answer:

2s + 4

Step-by-step explanation:

use the distributive property:

1/4 (8z + 16)

2s + 4

Done!

8 0
2 years ago
Simplest form <br> 7/15 - 1/5
Lunna [17]

Answer:

4/15

Step-by-step explanation:

7/15 - 3/15 = 4/15

8 0
3 years ago
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What temperature is 10 degrees les then 6 degrees Celsius
STALIN [3.7K]

Answer:

-4

Step-by-step explanation:

you say 6-10

which is -4

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HELPPPPP PLZZZZZZZ PLLLZZZ BRANLIESTTTT look THAT THE PICTURE
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Answer:

y is equal to or greater to one

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Step-by-step explanation:

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5 0
2 years ago
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The total mass of the Sun is about 2×10^30 kg, of which about 76 % was hydrogen when the Sun formed. However, only about 12 % of
nignag [31]

Answer:

A. 1.8 ×10^{30} Kg

B i. 3.0 × 10^{17} seconds

  ii. 9.6 × 10^{9} years

C. After 9.2 × 10^{9} (9.2 billion) years

Step-by-step explanation:

Given that the mass of the Sun = 2× 10^{30} Kg.

Mass of hydrogen when Sun was formed = 76% of 2× 10^{30} Kg

                            = \frac{76}{100}  ×2× 10^{30} Kg

                           = 1.52 × 10^{30} Kg

Mass of hydrogen available for fusion = 12% of 1.52 × 10^{30} Kg

                           = \frac{12}{100} × 1.52 × 10^{30} Kg

                           = 1.824 ×10^{30} Kg

A. Total mass of hydrogen available for fusion over the lifetime of the sun is 1.8 ×10^{30} Kg.

B. Given that the Sun fuses 6 × 10^{11} Kg of hydrogen each second.

i. The Sun's initial hydrogen would last;

                                     \frac{1.8*10^{30} }{6*10^{11} }

                                 = 3.04 × 10^{17} seconds

The Sun's hydrogen would last 3.0 × 10^{17} seconds

ii. Since there are 31536000 seconds in a year, then;

The Sun's initial hydrogen would last;

                                     \frac{3.04*10^{17} }{31536000}

                                 = 9.640 × 10^{9} years

The Sun's hydrogen would last 9.6 × 10^{9} years.

C. Given that our solar system is now about 4.6 × 10^{9} years, then;

                               \frac{9.6*10^{9} }{4.6*10^{9} }

                             = 2.09

So that;   2 × 4.6 × 10^{9} = 9.2 × 10^{9} years

Therefore, we need to worry about the Sun running out of hydrogen for fusion after 9.2 × 10^{9} years.

6 0
3 years ago
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