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3 years ago

0 = ax^2 + bx + c has a discriminate value of 0. How many solutions does the equation have

Mathematics

1 answer:

finlep [7]3 years ago

7 0

Answer:

2 or more

Step-by-step explanation:

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A new online music service has a collection of 1,500 songs. It expects to triple the number of songs each year for the next few

Rzqust [24]

Answer: y = (3^(x-1))*1500

Step-by-step explanation:

We want the relationship

y = f(x)

where y is the number of songs, and x is the number of years.

We know that in the first year, x = 1, the site has 1,500 songs.

The next year, x = 2, the number of songs is tripled, then we will have:

1,500*3 = 4500 songs.

The next year, x = 3, we will have: 3*(3*1500) = (3^2)*1500.

when x = 4, the number is tripled again:

3*(3^2)*1500 = (3^3)*1500

We already can see the pattern, for the year x, the site will have:

y = (3^(x-1))*1500 songs.

This is the equation we are looking for.

7 0

3 years ago

I need help..........

Marat540 [252]

Answer: 3rd one
Rearrange the original equation so it fits the model of : ax^2+bx+c=0
Then use the quadratic formula to find all possible answers.

5 0

3 years ago

Simplify the expression: –7(5 − u)

katovenus [111]

Answer:

-7(5-u)

Step-by-step explanation:

-7(5-u)

-7x5 -7x-u

-35+7u

7 0

3 years ago

Read 2 more answers

John has a boat that will travel at the rate of 15 kph in still water. He can go upstream for 35 km in the same time it takes to

Otrada [13]

Answer:

The boat traveling at 24 kph when John goes downstream.

Step-by-step explanation:

We are given the following in the question:

John has a boat that will travel at the rate of 15 kph in still water.

Let x be the speed of the current.

Speed of boat in upstream

$(15-x)\text{ kph}$

Speed of water in downstream

$(15+x)\text{ kph}$

Relation:

$\text{Speed} = \dfrac{\text{Distance}}{\text{Time}}$

We have to find the speed of boat in downstream.

Time to travel upstream for 35 km = Time to travel 140 km downstream

$\displaystyle\frac{35}{15-x}=\frac{140}{15+x}\\\\35(15+x) = 140(15-x)\\525 + 35x = 2100 - 140x\\175x = 1575\\x = 9$

Thus, speed of current is 9 kph.

Speed of boat in downstream = 15 + 9 = 24 kph.

Thus, the boat traveling at 24 kph when John goes downstream.

4 0

3 years ago

If each lap is 500 meters, how many laps will be needed to run 437.5 meters?

Musya8 [376]

Well if you subtract 437.5 from 500 you get 62.5 that is the difference between them but in fraction form it would be 5/8.

7 0

3 years ago