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notka56 [123]
3 years ago
6

I need help..........

Mathematics
1 answer:
Marat540 [252]3 years ago
5 0
Answer: 3rd one
Rearrange the original equation so it fits the model of : ax^2+bx+c=0
Then use the quadratic formula to find all possible answers.
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Can someone help me plz I will make brainliest. For correct answers only
VladimirAG [237]

Answer:

Step-by-step explanation:

1). Distributive Property of  multiplication over subtraction (Distributing the 5 and the 2)

2). Communtative Property of Equality (Moving terms around)

6 0
3 years ago
Write a polynomial function in factored form with double roots at -2 and 5 and the constant term of the polynomial in standard f
Amanda [17]

Answer:

f(x)=-0.4x^4+2.4x^3+8.4x^2-24x-40

Step-by-step explanation:

If -2 and 5 are double roots of the polynomial function, then the function expression is

f(x)=a(x-(-2))^2(x-5)^2\\ \\f(x)=a(x+2)^2(x-5)^2

Rewrite this function in standard form:

f(x)=a(x^2+4x+4)(x^2-10x+25)\\ \\f(x)=a(x^4-10x^3+15x^2+4x^3-40x^2+100x+4x^2-40x+100)\\ \\f(x)=a(x^4-6x^3-21x^2+60x+100)\\ \\f(x)=ax^4-6ax^3-21ax^2+60ax+100a

The constant term of the polynomial in standard form is -40, so

100a=-40\\ \\a=-\dfrac{40}{100}=-0.4

Therefore, the function expression is

f(x)=-0.4x^4-6\cdot (-0.4)x^3-21\cdot (-0.4)x^2+60\cdot (-0.4)x+100\cdot (-0.4)\\ \\f(x)=-0.4x^4+2.4x^3+8.4x^2-24x-40

7 0
4 years ago
Which is the best way to estimate 32% of 13?
RSB [31]

Answer:

32% of 13 is 3.84

Step-by-step explanation:

but if your doing estimate one of those it would be 1/3*12

hope that helped

5 0
3 years ago
Conservationists tagged 120 ​black-nosed rabbits in a national forest in 1990. In 1991​, they tagged 240 ​black-nosed rabbits in
Sauron [17]

Answer:

Hence after period of 9 years from 1990 t0 1999 will be 61438 rabbits.

Step-by-step explanation:

Given:

Population for rabbit obeys exponential law.

120 at 1990 and 240 1991 ...after 1 year time period

To Find:

After 9 year  time period how many rabbits will be there.

Solution:

Exponential law goes on present value and various value and time period and defined as ,

let Y be present value Y0 previous year value  and k exponential constant and t be time period.

So

Y=Y0e^(kt)

Here Y=240  ,Y0=120  t=1 year time period

So

240=120e^(k*1)

240/120=e^k

2=e^k

Now taking log on both side, [natural log]

ln(2)=ln(e^k)

ln(2)=kln(e)

k=ln(2)

k=0.6931

For t=9 year of time period

Y0=120,  t=9  ,k=0.6931

Y=Y0e^(k*t)

Y=120*e^(0.6931*9)

=120e^6.2383

=61438.48

=61438 rabbits

8 0
4 years ago
There are 12 appetizers; 4 are soups, 6 contain meat, and 2 do not. In how many different orders can 3 different appetizers be b
solniwko [45]
72 different orders, each soup can have a different meat and other* so take 4* 6* 3 because that is how many different combanations you can do

6 0
4 years ago
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