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3 years ago

I need help..........

Mathematics

1 answer:

Marat540 [252]3 years ago

5 0

Answer: 3rd one
Rearrange the original equation so it fits the model of : ax^2+bx+c=0
Then use the quadratic formula to find all possible answers.

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A proportional equation does not have a what?

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A proportional equation does not have a Y-intercept greater than 0.

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2 years ago

Points C and D divide the semicircle into three equal parts. Match the angles with their measures.

Tresset [83]

∠CAE = 120°
∠CAD = 60°
∠BAE = 180°
∠DEC = 30°

We start out with the fact that points C and D split the semicircle into 3 sections. This means that ∠BAC, ∠CAD and ∠DAE are all 60° (180/3 = 60).

Since it forms a straight line, ∠BAE is 180°.

Since it is formed by ∠CAD and ∠DAE, ∠CAE = 60+60 = 120°.

We know that an inscribed angle is 1/2 of the corresponding arc; since CD is 1/3 of the circle, it is 1/3(180) = 60; and this means that ∠DEC = 30°.

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3 years ago

Read 2 more answers

Please help me with this question

WINSTONCH [101]

Answer:

it is not linear

Step-by-step explanation:

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3 years ago

What is the point slope of an equation with slope of 3/5 that passes through the point (10,-2)

Verdich [7]

The answer would be B. It gives you the slope and a point on the graph so use that to your advantage. All of the answers show the slope and the slope in the right place, so for now it can be any of them. Then we get to the point (10,-2). For point slope form you would switch the signs for both x and y. So the Y would now be +2 and x would be -10. Y goes together with y, and X goes together with x. In this case y+-y= slope(X+-x) Substitute in for them. Y+2=3/5(X-10)

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3 years ago

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Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(4, 0), Q(0, −4), and R(−8, −4). Triangle P'Q'R' has

Whitepunk [10]

Answer:

Please find attached the required plot accomplished with an online tool

Part A:

1/4

Part B:

P''(-1, 0), Q''(0, -1), and R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent

Step-by-step explanation:

Part A:

Triangle ΔPQR has vertices P(4, 0), Q(0, -4), R(-8, -4)

Triangle ΔP'Q'R' has vertices P'(1, 0), Q'(0, -1), R'(-2, -1)

The dimensions of the sides of the triangle are given by the relation;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

Where;

(x₁, y₁) and (x₂, y₂) are the coordinates on the ends of the segment

For segment PQ, we place (x₁, y₁) = (4, 0) and (x₂, y₂) = (0, -4);

By substitution into the length equation, we get;

The length of segment PQ = 4·√2

The length of segment PR = 4·√10

The length of segment RQ = 8

The length of segment P'Q' = √2

The length of segment P'R' = √10

The length of segment R'Q' = 2

Therefore, the scale factor of the dilation of ΔPQR to ΔP'Q'R' is 1/4

Part B:

Reflection of (x, y) across the y-axis gives;

(x, y) image after reflection across the y-axis = (-x, y)

The coordinates after reflection of P'(1, 0), Q'(0, -1), R'(-2, -1) across the y-axis is given as follows;

P'(1, 0) image after reflection across the y-axis = P''(-1, 0)

Q'(0, -1) image after reflection across the y-axis = Q''(0, -1)

R'(-2, -1) image after reflection across the y-axis = R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent as the dimensions of the sides of triangle PQR and P''Q''R'' are not the same.

6 0

3 years ago