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2 years ago

Solve this equation. 1+1 = ?

Mathematics

1 answer:

max2010maxim [7]2 years ago

5 0

Answer:

Step-by-step explanation:

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Hi can someone help me with this?

zalisa [80]

Answer:

$2^{2}$ or 4

Step-by-step explanation:

7 0

2 years ago

The radius of a circle is 8 kilometers. What is the area?

Scorpion4ik [409]

Answer:

Area of the circle= $200.96 km^2$

Step-by-step explanation:

Area of a circle= $\pi *r*r$

For radius(r)=8 km

The area of the circle is :

= $\pi *8*8$

As:

$\pi =\frac{22}{7}=3.14$

Area of the circle:

$=3.14*8*8\\\\=3.14*64\\\\=200.96km^2$

The Area of the circle with the radius of $8km$ is $200.96 km^2$

7 0

2 years ago

Read 2 more answers

A truck is carrying cranberry juice, grape juice, and pineapple juice bottles in a ratio of

satela [25.4K]

Answer:

140

Step-by-step explanation:

7- Cranberry

2:Grape = 40 so 40/2 = 1

3:Pineapple

1= 20 juices

7+2+3 is 12

20 x 12 is 140

8 0

2 years ago

Read 2 more answers

Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt

-Dominant- [34]

Using the t-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

At the null hypothesis, it is tested if it does not outlast by more than 2 hours, that is, the subtraction is not more than 2:

$H_0: \mu_B - mu_A \leq 2$

At the alternative hypothesis, it is tested if it outlasts by more than 2 hours, that is:

$H_1: \mu_B - \mu_A > 2$

The sample means are: $\mu_A = 8.65, \mu_B = 11.23$

The standard deviations for the samples are $s_A = s_B = 0.67$

Hence, the standard errors are:

$s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934$

The distribution of the difference has mean and standard deviation given by:

$\overline{x} = \mu_B - \mu_A = 11.23 - 8.65 = 2.58$

$s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735$

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 2$ is the value tested at the hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{2.58 - 2}{0.2735}$

$t = 2.12$

The critical value for a right-tailed test, as we are testing if the subtraction is greater than a value, with a 0.05 significance level and 12 + 12 - 2 = 22 df is given by $t^{\ast} = 1.71$

Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

7 0

2 years ago

a family's monthly utility costs are phone 200 electric 100 Cable TV 100 water and gas 50 internet 50 by eliminating cable by wh

AleksandrR [38]

Answer:

500

Step-by-step explanation:

I'm not sure

6 0

3 years ago