Volume of the cone = 1/3π r^2 h
So, we are given that r = 9 and h = 12
plugging in all the known values
1/3 * (3.14) * 9 * 9 * 12
= 1017.36 cm³
or
≈1017.4 cm³
Answer: Similar - AA
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Answer:
X density = fXpxq and
Y" =InpXq
Now to find Y density FYpyq interms of the density of X we compare the density of X with Y"
fX = In
And PXq =pxq
Thus replacing x with y,
PXq = pyq
(a) Hence the density of Y is FYpyq
(b) at p0, fYpyq =fYp0q= 0
At 5s, FYpyq =5