How much less than 3x^2−7x+9 is 2x^2+4x−8 ? Thanks!!

1 answer:

maks197457 [2]3 years ago

8 0

Simplify.
3x^2−7x+9 - 2x^2+4x−8

1. 3x^2-2x^2 = x
2. -7x + 4x = -3x
3. 9 - 8 = 1

Combine.
x -3x +1

Thus, 2x^2+4x−8 is x -3x +1 less than 3x^2−7x+9

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