Question

Jeff is training for a walkathon.he walked 8.84 miles at an average speed 3.4 miles per hour. The he walked for a additional 1.6 hours at the same speed. How many hours did Jeff walk in all

Answer 1

Answer:

4.2 hours.

Step-by-step explanation:

We just have to find the time for each interval. The problem is giving us the time of the second interval, so we just need to find the time for the first one.

Jeff is moving at an average speed, that means the movement is modelled by

$d=st$

Where $d$ is distance, $s$ is speed and $t$ is time. Isolating the time and replacing given values we can find it

$t=\frac{d}{s} \\t=\frac{8.84mi}{3.4\frac{mi}{hr} } \\t=2.6 hr$

So, the first interval took 2.6 hours and the second interval took 1.6 hours. Therefore, the total number of hours Jeff walked is 2.6+1.6=4.2 hours.

Answer 2

About three hours

8.84 + 1.6 is 10.44 and then 10.44 divided by 3.4 is 3.07 or rounded to 3.1