<span>f(x)=5x+3/6x+7
This means that f(6/x) = [</span>5(6/x)+3] / [6(6/x)+7] = [ 30/x +3 ] / [36/x +7]
If we assume x≠0 , f(6/x) = [30 +3x]/ [36 + 7x]
g(x)=√<span> [ x^2-4x ]
</span>
g(x-4) = √ [ (x-4)^2-4(x-4) ] = √ [ x² -8x +16 -4x +16 ] = √ [ x^2-12x +32]
A page of two-dimensional arrays can be thought of as a three-dimensional array. Since 2-dimensional arrays are commonly expressed in tables or matrixes, therefore, if we put these tables or matrices in a page, the collection of matrices in a single page would now be structured into a 3D array.
The area of the trapezoid is the product of the height and the average of the two bases:
<span>30 (25 + 33)/2 = 30 (58)/2 = 30 (29) = 870 square yd. </span>
<span>But we want to exclude the area of the fountain. </span>
<span>Since it's circular its area is π times the square of its radius, or 16π square yd. </span>
<span>So the area of the park, excluding the fountain, is </span>
<span>870 - 16π square yd, </span>
<span>or about 820 square yd.</span>
Answer:
3) Prove the lengths are the same.
Step-by-step explanation:
Congruent is a measure of the lengths of the sides not the slopes.
