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Bumek [7]
3 years ago
14

5x(12-4)+3=? PLEASE HELP WILL MARK BRAINLIEST!!!!!

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
3 0

Answer:

D. 43

Step-by-step explanation:

first do everything inside paranthesis (12-4)=8

then multipy 8 by 5= 40

40+3=43

hope this helps

Studentka2010 [4]3 years ago
3 0

Answer:

43

Step-by-step explanation:

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Raul calculated that he would spend $125 on school supplies this year. He actually spent $87.50 on school supplies. What is Raul
dybincka [34]

Answer:

C 30%

Step-by-step explanation:

87.50/125= 0.70

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3 0
2 years ago
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The cost of tuition at a college is $12,000 and is increasing at a rate of 6% per year; 4 years.​
Mekhanik [1.2K]

Answer: $2880

Step-by-step explanation:

I = P • r • t

I = 12000 • 0.06 • 1460/365 (I used 1340/365 because there are 365 days in a year. 4 years = 1460)

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8 0
3 years ago
In the data set below, what is the range? 9, 4, 9, 2, 8, 2, 1
noname [10]
First put these in order from least to greatest.

1,2,2,4,8,9,9 is the correct order
Range is when we subtract the greatest value of our data set from the smallest so in our case it would be 9-1 which leaves us with our answer that 8 is your range.
7 0
3 years ago
Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
2 years ago
A circle whose center is the origin passes through the point (-5,12). Which point also lies on this circle?
schepotkina [342]
The answer is B(11, 2sqrt(12) )
proof

the main equation of the circle is   (x-x1)²+(y-y1)²=R²
where C(x1, y1) is the center 
so if the center is the origin, it is O(0,0), and the equation becomes
<span>  (x)²+(y)²=R²
</span>and the circle passes through the point (-5,2) so we can write 
(-5)²+12²=R², it implies R= sqrt(25+144)=sqrt(169)=13

and  for <span>B(11, 2sqrt(12) )     </span>11²+  (2sqrt(12))²= 121 + 48= 169= 13
it is checked.
3 0
3 years ago
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