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max2010maxim [7]
3 years ago
10

Mr. Howard lost money on his investments at a rate of $7 per day. Which expression shows how much money he lost over the course

of 5 days?
Mathematics
1 answer:
dalvyx [7]3 years ago
5 0

Answer:

7 x 5 = 35 or the amount lost

Step-by-step explanation:

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So I’m stuck on these 3 problems can anyone help me? If you can pls simplify the problems are: 20/26 ÷ 5 =? 28/56 ÷ 2 =? 75/90 ÷
Tamiku [17]

Answer:

2/13 or 0.15 ,  1/4 and 5 /18 or 0.28

Step-by-step explanation:

20/26 ÷ 5 =?

10/13 ÷ 5 = 2/13 or 0.15

28/56 ÷ 2 =?

1/2 ÷ 2 = 1/4

75/90 ÷ 3 =?

5/6 ÷ 3 =5 /18 or 0.28

7 0
2 years ago
what property is illustrated by the statement 1×y=y? A. MULTIPLICATIVE IDENTY B. COMMUTATIVE C. ASSOCIATIVE PROPERTY OF MULTIPIL
vesna_86 [32]

This has nothing to do with zero. It is not mentioned at all. If y = 0 then D would apply, but no such restriction is present. The answer is not D

There has to be 3 numbers multiplied together to use the associative properties of multiplication as in (2 * 3) * 5 = 2 * (3 * 5) . The order that we multiply does not matter.

The commutative property could be true, and it is you second best answer (believe it or not) but, 1 * y = y * 1 is kind of trivial. So don't pick B until we find out about A

This often shows up 1 * x is the same thing as x. This is called the multiplicative identity.

A. <<<< Answer.

5 0
4 years ago
Read 2 more answers
Evaluate: 1/3(-15 + 3/2)
trasher [3.6K]

Answer:

-4.5 is correct answer

Step-by-step explanation:

\frac{1}{3} ( - 15 +  \frac{3}{2} ) \\  =  \frac{1}{3} (  \frac{ - 30 + 3}{2} ) \\ =   \frac{1}{3} (  \frac{ - 27}{2} ) \\     = \frac{ - 9}{2}

hope it helped you:)

7 0
4 years ago
A business school professor uses multiple choice tests. Each question on his exams has five possible answers which are assumed t
avanturin [10]

Answer:

a. The null hypothesis for this test is that the observed distribution is the same as uniform distribution

b. The degrees of freedom do you have for this test is 4

c.  The calculated value of the test statistic is 9.250

Step-by-step explanation:

a. According to the given data we can conclude that the null hypothesis for this test is that the observed distribution is the same as uniform distribution.

b. In order to calculate the degrees of freedom do you have for this test we would have to make the following calculation:

degrees of freedom=k-1

degrees of freedom=5-1

degrees of freedom=4

c. In order to calculate the value of the test statistic first we have to calculate the frecuency expected as follows:

expected frecuency=total observed frecuency/total number of category

expected frecuency=1,000/5

expected frecuency=200

Hence, to calculate the value of the test statistic we have to calculate the following formula:

x∧2=∑(fo-fe)∧2/fe

=(185-200)∧2/200+(230-200)∧2/200+(215-200)∧2/200+(180-200)∧2+(190-200)∧2

=9.250

The calculated value of the test statistic is 9.250

7 0
4 years ago
There are 58 students in a classroom with 7
lys-0071 [83]

8x7=56, so 56 students can sit at a table, 58-56=2 students without a table.

Your answer would be 2.

6 0
3 years ago
Read 2 more answers
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