Using the z-distribution, it is found that a sample of 171 should be selected.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:

The margin of error is:

In which:
is the sample mean.
is the standard deviation for the population.
For this problem, the parameters are:

Hence we solve for n to find the needed sample size.





n = 170.7.
Rounding up, a sample of 171 should be selected.
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer:
it is 1/8÷2/5= 5/16
Step-by-step explanation:
did that help??????????????????
Answer:
Ok so im not to sure but I think its 40.62 but i could be wrong since it was worded odd
Step-by-step explanation
Answer:
3p=q-2r
p= (q-2r)/3
Step-by-step explanation:
Answer:
60
Step-by-step explanation:
5 ( 9 + d )
Let d=3 and substitute it in
5(9+3)
According to PEMDAS, we do what is in the parentheses first
5(12)
Now we multiply.
60