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katen-ka-za [31]
3 years ago
6

Find the equation of the line that passes through (-4,1) and is parallel to 1/2

Mathematics
1 answer:
Bumek [7]3 years ago
3 0

Answer:

y = 1/2 x + 3

Step-by-step explanation:

Since the lines are parallel, m1 = m2

y — y1 = m(x — x1)

Data obtained from the question include:

m = 1/2

x1 = —4

y1 = 1

y — y1 = m(x — x1)

y — 1 = 1/2(x — —4)

y — 1 = 1/2(x + 4)

y —1 = 1/2x + 2

y = 1/2x + 2 + 1

y = 1/2 x + 3

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Simplify (x^2)^3*5x/6x^2*15x^3
nasty-shy [4]

When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2

<h3>Data obtained from the question</h3>
  • [(x^2)^3 × 5x] / [6x^2 × 15x^3]
  • Simplification =?

<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>

[(x^2)^3 × 5x] / [6x^2 × 15x^3]

Recall

(M^a)^b = M^ab

Thus,

(x^2)^3 = x^6

  • [(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]

Recall

M^a × M^b = M^(a+b)

Thus,

x^6 × 5x = 5x^(6 + 1) = 5x^7

6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5

  • [x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5

Recall

M^a ÷ M^b = M^(a - b)

Thus,

5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2

Therefore,

  • [(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2

Learn more about algebra:

brainly.com/question/2768008

#SPJ1

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