The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
(x1, y1) = (3,8)
(x2, y2) = (1,0)
Answer: 19 macaroons
Step-by-step explanation:
Let's create an equation to represent this situation. Let x represent the number of macaroons that Em made.
33=x+x+5
33=2x+5
33-5=2x+5-5
28=2x
28/2=2x/2
14=x
This means that Em made 14 macaroons.
14+5=19
Therefore, Jim baked 19 macaroons.
first get all variables on the same side, then use elimination to solve.
x = -3
y = -11
1: 5 2: 9 or 10
For question 1 we can round 115 to 100, 5x100 is 500 which is closer to 545 than 7x100 = 700.