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Nikolay [14]
3 years ago
12

Evaluate the expression for k=6 42/k

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
5 0
42/6 = 7! Happy to help
densk [106]3 years ago
3 0
If I understand what you are asking, you should input 6 in for k in the expression 42/k:

42/6 = 21/3 = 7

Answer: 7
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Describe the error in the work shown below.
Katena32 [7]

Answer:

the bottom equation should be 18+30=3(6+10)

Step-by-step explanation:

6(3+10) = 18+60 which equals 78

78 does not equal 18

5 0
3 years ago
Estimate -9 1/6 + 2 1/3 + (-1 7/8) I have more questions so if you want more just simply ask.
BigorU [14]

-8.70833333333 about but you can round to the nearest tenth (-8.7) or nearest whole number (-9)

4 0
3 years ago
HELPPPPP IM GIVING 50 POINTS FOR THIS !
azamat

4 cups = 1 quart

16 cups = 4 quarts

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8 0
3 years ago
Read 2 more answers
Can u plz help me?...
Westkost [7]

Answer:

a  4 1/5

b  7 7/24

Step-by-step explanation:

a  7/9 * 5 2/5

Change the mixed number to an improper fraction

7/9 * (5*5+2)/5

7/9 * 27/5

Rewrite

7/5 * 27/9

7/5 * 3

21/5

Change this back to a mixed number

5 goes into 21 4 times  (4*5 = 20 ) with 1 left over

4 1/5


b  1 3/4 * 4 1/6

Change to improper fractions

(4*1+3)/4  * (6*4+1)/6

7/4 * 25/6

175/24

Change back to a mixed number

24 goes into 175 7 times  (7*24 =168 ) with 7 left over

7 7/24

3 0
3 years ago
Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form
Alex787 [66]

Answer:

y=-\frac{2}{5}x-\frac{1}{5}

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

  • m is the slope
  • b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

m = -\frac{2}{5}

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-\frac{2}{5}x + b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

  • (-3,1). When x of the line is -3, y of the line must be 1.
  • (2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: y=-\frac{2}{5}x + b. b is what we want, the --\frac{2}{5} is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

  • (-3,1). y = mx + b or 1=-\frac{2}{5} * -3 + b, or solving for b: b = 1-(-\frac{2}{5})(-3).b = -\frac{1}{5}.
  • (2,-1). y = mx + b or -1=-\frac{2}{5} * 2 + b, or solving for b: b = 1-(-\frac{2}{5})(2). b = -\frac{1}{5}.

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points  (-3,1) and (2,-1) is y=-\frac{2}{5}x-\frac{1}{5}

8 0
3 years ago
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