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Kaylis [27]
3 years ago
9

Rewrite the slope intercept equation of the line y = 2x + 5 in standard form. A) 2x - y = -5 B) 2x + y = 5 C) -2x - y = -5 D) 2x

+ y = -5
Mathematics
1 answer:
goldenfox [79]3 years ago
3 0

Answer:

(A) 2x-y=-5

Step-by-step explanation:

Slope intercept form of equation of line is y = mx+c \ where\ m\ is \ slope

The standard form of equation is Ax + By + C = 0

Now let m=\frac{A}{B}therefore, m =\frac{2}{1}\ which\ gives\ A = 2and\ B = 1  

substituting the value of A and B  in slope intercept form,

y = \frac{A}{B} x+5\\\y = \frac{2}{1} x+ 5\\By\ simplifying,\\1y = 2x + 5\\on\ rearranging\ the\ above\ equation \\2x-y=-5\\which\ gives\ a\ standard\ form\ of\ equation\ Ax +By +C= 0\ where\ A= 2,\ B= (-1)\ and\ C = 5

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2 years ago
Select the locations on the number line to plot the points 9/2 and −7/2 .
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3 years ago
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3 years ago
Given the functions f(x) = 2x -1 and g(x) =
Novosadov [1.4K]

Answer:

Please check the explanation.

Step-by-step explanation:

Given

  • f(x) = 2x - 1
  • g(x) =  2 - x

a)

f(x) + g(x) = (2x - 1) + (2 - x)

                = 2x -1 + 2 - x

                = x + 1

b)

f(x) - g(x) = (2x - 1) - (2 - x)

              = 2x - 1 - 2 + x

               = 3x - 3

c)

g(-5) - f(-5)

Putting x = -5 in g(x) = 2 - x

g(x) = 2 - x

g(-5) = 2 - (-5) = 2+5 = 7

Putting x = -5 in f(x) = 2x - 1

f(x) = 2x - 1

f(-5) = 2(-5) - 1

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Thus,

g(-5) - f(-5) = 7 - (-11) = 7+11 = 18

d)

f(x).g(x) = (2x - 1) (2 - x) = -2x² + 5x - 2

e)

f(g(x)) = f(2-x)

          = 2(2-x)-1

          = 4-2x-1

          = 3-2x

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otez555 [7]
Your answer is 13,000
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