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Vedmedyk [2.9K]
3 years ago
7

Equilateral, isosceles, and scalene are ways in which you can classify triangles by their ___.

Mathematics
1 answer:
NeX [460]3 years ago
8 0

Answer:

b sides

Step-by-step explanation:

the sides will have markings so you wont need the specific angles

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(2 x + 1):15=(x-1):7​
GalinKa [24]
(2 x + 1):15=(x-1):7
7(2x+1)=15(x-1)
14x+7=15x-15
14x-15x=-15-7
-x=-22
x=22
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Help pls im to stupit ;(
Mrac [35]

Answer:

48.25

Step-by-step explanation:

ITS EDITED BTW

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what is the length of tw¯¯¯¯¯¯ ? segment t w with point u between t and w. segment t u is marked congruent to segment u w. segme
Gennadij [26K]
T________U________W
        16
TU=UW
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3 years ago
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5x-4y=19<br> x+2y=8<br> solve the simaltaneous equation
STatiana [176]

Answer:

( 5, 3/2 )

x = 5

y = 3/2

Step-by-step explanation:

5x - 4y = 19

x + 2y = 8

-------------------

2(x + 2y = 8) = 2x + 4y = 16

----------------------

5x - 4y = 19

2x + 4y = 16

7x = 35

÷7    ÷7

x = 5

-----------------------

x + 2y = 8

5 + 2y = 8

-5          -5

2y = 3

÷2   ÷2

y = ( 3/2 )

I hope this helps!

8 0
2 years ago
The area of a field shaped like a right triangle is 750yd^2.One leg of the field is fenced with wood costing $5/yd. the remainde
Elenna [48]
Assume that
 a and b = the two legs of the right triangle. 
 c =  the hypotenuse.

The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500               (1)

The perimeter is 150yd, therefore
a + b + c = 150         (2)

Let the side fenced with wood be a, at $5/yd.  Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
 5a + 10b + 10c = 1200            
or
a + 2b + 2c = 240         (3)

From (2), obtain 
c = 150 - a - b              (4)

Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60

From (1), obtain
60b = 1500
b = 25

From (4), obtain
c = 150 - 60 - 25 = 65

Answer:
A. The length of the leg fenced with wood is 60 yd.
B.  The length of the leg fenced with steel is 25 yd.


5 0
3 years ago
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