Answer:
B. As the distance between loci increases, some multiple crossovers go undetected such that the relationship between recombination frequency and map distance ceases to be linear.
Explanation:
When calculating recombination frequencies, and hence, map distances, we might notice that these distances are not completely additive. They might vary. <em>For example, let us say that we have three genes, A, B, and C, in that order. </em>We calculated that the <em>distance between A and B equals 5.9</em> MU and that <em>B and C are 19.5 MU apart.</em> According to this, we might say that the <em>total distance between A and C is 25.4 MU (5.9 + 19.5). </em>However, after a<em> two-point calculation between A and C, the value equals 23.7 MU. </em>
The recombination frequency between these two genes located in the extremes and far apart underestimate the actual genetic distances between them because there might occur other crossing-overs that were not detected. This is <em>when calculating the distance between A and C, we probably will not detect the occurrence of a double recombinant between them, and hence, we might sub-estimate the real distance.</em>
The relationship between the actual map distance (number of crossing overs) and the recombination frequency between two loci, is not lineal. The farther apart are the two genes, the worse is the distance estimation.
The lack of iron makes them crave ice.
Answer:
D
Explanation:
Mutation can be harmful and it can have no effect.
The <em>Hydra </em>offspring will also have 30 chromosome.
Explanation:
- Budding is a method of asexual reproduction.
- Asexual reproduction takes place through mitosis where diploid cells divide to give rise to identical cells with same chromosome number.
- Hydra reproduces through budding thus, if the parent hydra has 30 chromosome then the offspring will also have 30 chromosome.
Answer:
D
Explanation:
it's mollusk because humans eat oysters and clams and they are part of the mollusk family. I'm not sure but im pretty sure
