Question

The rectangular room shown has a length of 20 ft, width of 48 ft, and height of 10 ft. Use the Pythagorean Theorem to find length BC and length AB. Round to the nearest tenth, if necessary

Answer 1

For the diagonal of the floor:
20^2 + 48^2= c^2
400+2304= c^2
c=52
For the diagonal of the cube:
52^2 + 10^2 = c^2
2704+100=c^2
c=52.95
Rounded= 53
Tell me if this helps!!!

Answer 2

Answer:

A, the rectangular room will be in the shape of cuboid, whose dimension are

Length = 20 ft, Width=48 ft and Height = 10 ft

Length of Diagonal of floor

 $=\sqrt{L^2+W^2}\\\\=\sqrt{20^2+48^2}\\\\=\sqrt{400+2304}\\\\=\sqrt {2704}\\\\=52$

Length of Diagonal of floor=52 ft

Length of diagonal of Room

$=\sqrt{L^2+W^2+H^2}\\\\=\sqrt{20^2+48^2+10^2}\\\\=\sqrt{400+2304+100}\\\\=\sqrt{2804}\\\\ =52.95$

Length of diagonal of Room=52.95 ft