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stellarik [79]
3 years ago
9

Solve the equation. -4(3 - 2x) + 2x = 2x - 8 A) x = 2 B) x = -1 C) x = 1/ 2 D) x = 1/ 3

Mathematics
2 answers:
sertanlavr [38]3 years ago
7 0
-4(3-2x)+2x=2x-8
First Distribute your -4 to get -12+8x+2x=2x-8
Then combine like terms to get -12+10x=2x-8
Add 8 over to the -12 to get -4+10x=2x
Subtract 10x from 2x to get -4=-8x
Finally, divide -4 by -8x to get x=1/2.
The correct answer is Letter C.
vaieri [72.5K]3 years ago
4 0
-4(3-2x)+2x=2x-8
distribute -4 through (3-2x)= -12+8x
-12+8x+2x=2x-8
Cancel out 2x by subtracting it from both sides.
-12+8x=-8
Add 12 to both sides in order to get the -8x alone,
8x=4
Divide both sides by 8,
you will get 1/2 and that is C).
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Let us make a list of all the details we have

We are given

The cost of each solid chocolate truffle = s

The cost of each cream centre chocolate truffle = c

The cos to each chocolate truffle with nuts = n

The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25

That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)

The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75

That is 10s+5c+10n = $68.75

The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00

That is 12s+12n=$66.00

Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.



6 0
4 years ago
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vovangra [49]

A

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r = \frac{21}{7} = \frac{63}{21} = \frac{189}{63} = 3

B

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C

the n th term of a geometric sequence is

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where a_{1} is the first term in the sequence

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3 0
3 years ago
If an airplane descends 15 feet every 1.45 seconds, how far would the airplane travel in three and a half minutes? The equation
NemiM [27]

\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

The air plane descends 15 feels every 1.45 seconds, so it's unit rate is :

\qquad \sf  \dashrightarrow \:  \dfrac{15}{1.45} \:  \:  ft / sec

Now we have to calculate the descent in 3.5 minutes ~

\qquad \sf  \dashrightarrow \:  \dfrac{15}{1.45} \:  \:   \times 3.5 \times 60

\qquad \sf  \dashrightarrow \: 2172.41 \:  \: ft

So, the airplane descends 2172.41 feels in three and a half minutes ~

5 0
2 years ago
Brainlyest
evablogger [386]
A. 36/a
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3 years ago
8 + 6 + 12 = __ + 12 + 6
Zielflug [23.3K]

Answer:

The number 8 goes in the blank,

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Hope this helps!

3 0
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