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3 years ago

Which figures are similar?

Mathematics

1 answer:

Tomtit [17]3 years ago

5 0

Your answer is b ~d and e~f and a~ c

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3/4 x = 2/5<br><br> please answer this

Vlada [557]

Answer:

= 8 /1 5

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Solve this linear system 28x + 44y = 964.40 21x + 33y = 723.30

Sladkaya [172]

28x + 44y = 964.40

21x + 33y = 723.30

Let's multiply the first equation by 4 and the second by -4

84x + 176y = 3857.6

-84x - 132y = -2893.2

Add the equations together.

0 + 44y = 964.4

Simplify

44y = 964.4

Divide both sides by 44

y = 964.4/44

Since we have the value of y, let's plug 964.4/44 into y for the first equation.

28x + 44(964.4/44) = 964.40

Simplify the left side

28x + 964.4 = 964.4

Subtract 964.4 from both sides

28x = 0

Divide both sides by 0

x = 0

In conclusion,

y = 964.4/44

x = 0

3 0

3 years ago

. Parallelogram ABCD,

anastassius [24]

Diagram not attached, please add the question.

8 0

3 years ago

Rosy waxes 2/3 of her car with 1/4 bottle of car wax. At this rate what fraction of the bottle of car wax will Rosy use to wax h

Dmitry_Shevchenko [17]

⅜ of the bottle. Hope this helps!

4 0

3 years ago

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Carlos is filling a spherical balloon with water. if he increases the volume of the balloon from 4,188.79 cubic centimeters to 1

Harrizon [31]

We know that the volume of a sphere of radius r is given by

$V=\frac{4}{3}\pi r^3$

Now, we have been given the initial volume was 4,188.79 cubic centimeters. Let us find the radius at this time.

Substituting the value of volume in the above equation, we get

$4,188.79=\frac{4}{3}\pi r^3\\
\\
4\pi r^3=4,188.79 \times 3\\
\\
r^3=\frac{4188.79 \times 3}{4\pi}\\
\\
r^3=1000\\
\\
r=10$

Now, the final volume is given by 14,137.167 cubic centimeters. Thus, we have

$14137.167 =\frac{4}{3}\pi r^3\\
\\
4\pi r^3=14137.167 \times 3\\
\\
r^3=\frac{14137.167\times 3}{4\pi}\\
\\
r^3=3375\\
\\
r=15$

Now, let us find the surface areas for these two radii.

For $r=10$

Surface area is given by

$S=4\pi r^2\\
\\
S=4\times 3.14 \times (10)^2\\
\\
S=1256 \text{ square centimeters}$

Similarly, for

$r=15\\
\\
S=4\times 3.14\times (15)^2\\
\\
S=2826 \text{ square centimeters}$

Therefore, the increase in the surface area is given by

$\Delta S= 2826-1256= 1570 \text{ square centimeters}$

Hence, the average rate at which the surface area is changing is given by

$\frac{1570}{12}=130.8$

Therefore, the average rate at which the surface area is changing is given by 130.8 square centimeters per second.

7 0

4 years ago