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Tems11 [23]
3 years ago
6

Help: I am a number between 60 and 100. My ones digit is six less than my tens digit. I am a prime number.

Mathematics
2 answers:
marysya [2.9K]3 years ago
8 0
The correct answer is 97 if I’m not mistaken hope you have a wonderful day
Reptile [31]3 years ago
5 0

Answer:

Let's name the digit:

x- ones digit

y - tens digit

we know that x=y-2.

Now, y can be 6,7,8,9 (the number is between 60 and 100 (so depending on your understanding of "between", 0 is also possible. but then the number would have to have -2 as its ones digit, so in any case, it's not possible).

So the possibilities with x=y-2:

64

75

86

97

Out of those 64 and 86 are even, so they can't be prime.

75 has 5 in its ones number: it's divisible by 5.

so the correct answer is 97.

Step-by-step explanation:

Hope this helps!

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Hello there! :)

\sqrt{81}

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~Just an emotional teen listening to her favorite song "Try Everything"

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Check the picture below.

\bf \textit{vertex of a vertical parabola, using coefficients}
\\\\
h=\stackrel{\stackrel{a}{\downarrow }}{-5}t^2\stackrel{\stackrel{b}{\downarrow }}{+92}t\stackrel{\stackrel{c}{\downarrow }}{+16}
\qquad \qquad 
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Step-by-step explanation:

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Please please please help
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Step-by-step explanation:

m1=m2=m3=m5

m4=m6=m7

find m1,m2,m3 or m5

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