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3 years ago

11

Which two substances bind using a lock-and-key mechanism?

1 answer:

kherson [118]3 years ago

4 0

Answer:

enzyme and substrate. reactant and substrate. substrate and product.

Step-by-step explanation:

You might be interested in

What is (3²-2³)⁶⁶ total

horrorfan [7]

Answer:

1

Step-by-step explanation:

(3²-2³)⁶⁶ = (9 - 8)⁶⁶ = (1)⁶⁶ = 1

6 0

3 years ago

Solve the following system of equations algebraically and check.<br><br> y=x^2+3x+4<br> y-x=7

FinnZ [79.3K]

Y=x^2+3x+4
y-x=7

x^2+3x+4-x=7
x^2+2x+4=7
(factor) x^2+2x-3=0
(x+3)(x-1)=0
X= -3 and X=1
(Plug x in for y)
Y= 1^2+3(1)+4
Y=8
(Check your answer on the second equation)
8-1=7
7=7 (Which is the solution)

5 0

3 years ago

Can anyone answer this?<br> x+1<5

Sliva [168]

X + 1 < 5
x < 5 - 1
x < 4

u basically solve it like equations except for one important rule....with inequalities, when u multiply/divide by a negative number, the inequality sign changes directions. But we didn't have to deal with that rule in this particular problem

5 0

3 years ago

Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=9\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

so

$A=(12)(7)-(8)(3)$

$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

so

$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

so

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

so

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

7 0

3 years ago

Algebra help please

leva [86]

The value of a would be 4.2, because the negatives cancel out each other.

4 0

3 years ago