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Lerok [7]
3 years ago
14

AA, SAS, SSS or not similar ?

Mathematics
1 answer:
Mariana [72]3 years ago
6 0

Answer:

SSS

Step-by-step explanation:

KN / PD = 54/24 = 2.25

KB / PF = 49.5/22 = 2.25

BN / DF = 40.5/18 = 2.25

ΔKBN ~ PDF   (SSS) : two triangles are similar, their corresponding sides are in equal proportion.

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You roll a 6-sided die.
Lerok [7]

Answer:

\huge\boxed{\text{P(not factor of 35) = } \frac{2}{3}}

Step-by-step explanation:

We can use basic probability to find the probability that this roll is not a factor of 35.

First off, we know that with a six sided die there are 6 possible things we can roll.

1, 2, 3, 4, 5, or 6

Now, what are the factors of 35? The factors of 35 will be any whole number that can be multiplied by another whole number to get 35.

  • We know 1 \cdot 35 = 35, so two factors are 1 and 35.
  • We know 5 \cdot 7 = 35, so two factors are 5 and 7.

Therefore, the factors of 35 are 1, 5, 7, 35.

Both 5 and 7 are inside the range of 1-6. So the probability of rolling a side that's a factor of 35 will be  \frac{2}{6} = \frac{1}{3} since there are two factors and 6 possible options.

This means, logically, there is a  \frac{4}{6} = \frac{2}{3}  chance of not rolling a factor of 35.

Hope this helped!

5 0
3 years ago
If 4x - 8 = 4 , find the value of x​
Wittaler [7]

Answer:

x=3

Step-by-step explanation:

4x-8=4

4x=12

4x/4=12/4

x=3

3 0
3 years ago
Read 2 more answers
X * X *X*X*X*X*XX hejfsghjjhffvbjjk
Mumz [18]
WHAT DOES THIS MEAN?
5 0
3 years ago
What is the area of this circle?<br><br> a 1,017.36<br> b 254.34<br> c 28.26<br> d 56.52
Licemer1 [7]

Answer:

b

Step-by-step explanatiobn:

b

5 0
2 years ago
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Helpppppppppppppppppppppp..... .......<br><br><br>​
morpeh [17]

Answer:

{ \sf{( \sec \theta -  \csc \theta)(1 +  \tan \theta +  \cot \theta) }} \\  = { \sf{( \sec \theta +  \tan \theta \sec \theta +  \cot  \theta \sec  \theta) - ( \csc  \theta -   \csc \theta \tan  \theta -  \csc \theta \cot  \theta)}} \\  = { \sf{( \sec \theta +  \sec \theta \tan  \theta +  \csc  \theta) - (  \csc  \theta -  \sec \theta -  \csc  \theta \cot   \theta)}} \\  = { \sf{ \sec  \theta \tan  \theta +  \csc \theta \cot \theta }} \\ { \bf{hence \: proved}}

3 0
3 years ago
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